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➷ Substitute the first 3 values in (1, 2, 3)
(1)^2 + 20 = 21
(2)^2 + 20 = 24
(3)^2 + 20 = 29
The first 3 terms would be 21, 24 and 29
For the second part, just keep going on until you reach 50
(4)^2 + 20 = 36
(5)^2 + 20 = 45
(6)^2 + 20 = 20 = 56 (this is larger than 50 so it doesn't count)
It would be 5 terms
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Answer:
w || n and n ⊥ m
Step-by-step explanation:
To find out which statement is true, recall the following:
1. 2 lines are said to be parallel to each other if they do not intersect at any given point and are of the same distant apart. Parallel is denoted by ||
2. 2 lines are said to be perpendicular if both lines intersect at a right angle. It is denoted by ⊥
==>From the diagram given, we can see that w and n are of the same distant apart and they do not intersect at any given point.
Also, we can see that n and m intersect at point X to at right angle.
Therefore, we can conclude that w || n and n ⊥ m
28.04996
Step-by-step explanation:
a² + b² = c²
(2x)² + x² = 62²
4x² + x² = 3844
5x² = 3844
x² = 3844÷5
x² = 768.8
x =
![\sqrt{768.8}](https://tex.z-dn.net/?f=%20%5Csqrt%7B768.8%7D%20)
x = 28.04996
I hope this is right. Apologies if it is not.
Answer:
![v=\frac{3\left(-z+5\right)}{5}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B3%5Cleft%28-z%2B5%5Cright%29%7D%7B5%7D)
Step-by-step explanation:
im too good no ty
<3
Red
Answer:
![\frac{1}{5}\frac{in}{miles}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%5Cfrac%7Bin%7D%7Bmiles%7D)
Step-by-step explanation:
we know that
The original scale of the map is
![\frac{2}{30}\frac{in}{miles}=\frac{1}{15}\frac{in}{miles}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B30%7D%5Cfrac%7Bin%7D%7Bmiles%7D%3D%5Cfrac%7B1%7D%7B15%7D%5Cfrac%7Bin%7D%7Bmiles%7D)
If the map is enlarged to 3 times its size
then
the new scale will be
![\frac{2*3}{30}\frac{in}{miles}=\frac{6}{30}=\frac{1}{5}\frac{in}{miles}](https://tex.z-dn.net/?f=%5Cfrac%7B2%2A3%7D%7B30%7D%5Cfrac%7Bin%7D%7Bmiles%7D%3D%5Cfrac%7B6%7D%7B30%7D%3D%5Cfrac%7B1%7D%7B5%7D%5Cfrac%7Bin%7D%7Bmiles%7D)