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3 years ago

Help me plzzz with my hw

Mathematics

1 answer:

Ivenika [448]3 years ago

7 0

Answer:

w || n and n ⊥ m

Step-by-step explanation:

To find out which statement is true, recall the following:

1. 2 lines are said to be parallel to each other if they do not intersect at any given point and are of the same distant apart. Parallel is denoted by ||

2. 2 lines are said to be perpendicular if both lines intersect at a right angle. It is denoted by ⊥

==>From the diagram given, we can see that w and n are of the same distant apart and they do not intersect at any given point.

Also, we can see that n and m intersect at point X to at right angle.

Therefore, we can conclude that w || n and n ⊥ m

You might be interested in

The sum of the sequence of 685+678+671+664+...+6

lukranit [14]

Answer:

Sum of the sequence (Sn) = 33,859

Step-by-step explanation:

Given:

Sequence = 685+678+671+664+...+6

Find:

Sum of the sequence (Sn)

Computation:

a = 685

d = 678 - 985 = -7

an = 6

an = a+(n-1)d

6 = 685+(n-1)(-7)

-679 = (n-1)(-7)

97 = n-1

n = 98

So,

Sum of the sequence (Sn) = (n/2)[a+an]

Sum of the sequence (Sn) = (98/2)[685+6]

Sum of the sequence (Sn) = (49)(691)

Sum of the sequence (Sn) = 33,859

3 0

3 years ago

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for h:

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for h.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

3 years ago

A train leaves boston at 2:00 pm. a second train leaves the same city in the same direction at 6:00 pm. the second train travels

AURORKA [14]

$\boxed {\boxed { \text {Distance = Speed x Time}}}$

First Train:
Time taken = 9 hours (2pm to 11pm)
Let the speed be x
Distance = Time x Speed = 9x

Second Train:
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)

Since both the distance they traveled are the same, we equate the distance to solve for x.

Solve for x:
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60

Find the speed:
x = 60 mph
x + 48= 108 mph

Answer: The spend of the two trains are 60 mph and 108 mph.

3 0

3 years ago

Marcel bought a new pair of inline skates. Each

g100num [7]

Answer:

1288.05

Explanation:

41mm=r

2(pi)r=257.61

257.61x5=1288.05

4 0

3 years ago

Please answer from the question above :)

AlekseyPX

Answer:

205/6

Step-by-step explanation:

The question simply asks us to plug in 45 minutes into the given equation. In the graph, we see that y-axis is defined to be time. Therefore we set y=45 and solve for x.

45=-6/5x+86

-41=-6/5x (subtract 86 from both sides)

-41*(-5)=-6/5x*(-5) (multiply both sides by -5)

205=6x (divide both sides by 6)

205/6=x

4 0

3 years ago