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Bas_tet [7]
3 years ago
7

A distance of 30 miles on a map is represented by a 2-inch line. If the map is enlarged to 3 times its size, what will be the sc

ale of the enlarged map?
PLEASE HELP!
Mathematics
1 answer:
vichka [17]3 years ago
4 0

Answer:

\frac{1}{5}\frac{in}{miles}

Step-by-step explanation:

we know that

The original scale of the map is

\frac{2}{30}\frac{in}{miles}=\frac{1}{15}\frac{in}{miles}

If the map is enlarged to 3 times its size

then

the new scale will be

\frac{2*3}{30}\frac{in}{miles}=\frac{6}{30}=\frac{1}{5}\frac{in}{miles}

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Find (a) the amplitude, (b) the wavelength, (c) the period, and (d) the speed of a wave whose displacement is given by y= 1.5 co
leonid [27]

Answer with Step-by-step explanation:

We are given that displacement of wave

y=1.5cos(0.68x+37t)

Where y in cm  and t in sec.

a.Compare it with

y=Acos(kx+\omega t)

Amplitude of wave=A

We get A=1.5

Amplitude=A=1.5  cm

b.k=0.68

\frac{2\pi}{\lambda}=0.68

\lambda=\frac{2\times 3.14}{0.68}=9.2 cm

Using \pi=3.14

Wavelength of the wave=9.2 cm

c.Period=\frac{2\pi}{T}=\omega

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Speed of the wave=54.1 cm/s

8 0
3 years ago
In June 1990, a small academic press published an initial run of 2,500 copies of linguist Chloe Vermeulen’s first book, Speech a
GREYUIT [131]

Answer:

A) 1525

B) 4636

C) 8479

Step-by-step explanation:

Lest say that The book had been sold x copies in the period of June 1990-June 1995. And we know that the book had been sold 152*x/100 copies in the period of June 1995–June 2000. By June 2000 in total 3843 book had been sold. Therefore number of the copies that sold in the period of June 1990-June 1995 is:

252*x/100=3843\\x=1525

number of the copies that sold in the period of June 1995-June 2000 is:

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For the period June 2000–June 2005 2318*2=4636 book had been sold.

5 0
3 years ago
Use the six side-by-side boxplots of on-time graduation rates that you produced to match descriptions to colleges. You may use a
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Answers and Step-by-step explanations:

a)

According to the question, the college that has one of the lowest medians and least consistence in the graduation rates is defined as worst college.

From the provided side by side boxplots, college A has one of the lowest medians. Moreover, the difference between the first and third quartile is much higher than the other colleges. That is, IQR is high for this college. Therefore, there is least consistence in graduation rate.

Hence, the correct answer choice is 'A'

b)

According to the question, the college that has highest median and fair consistence in the graduation rates is defined as best college.

From the provided side by side boxplots ,college D has the highest median. Moreover, the difference between the first quartile and the median is same as the difference between the first quartile and the median. Therefore, there is a fair consistence in graduation rate.

Hence, the correct answer choice is D.

c)

According to the question, the college  has the the lowest median and best consistence in graduation rates.

From the provided side by side boxplots ,college B has the lowest median. Moreover, the difference between the first and third quartile is much lower than the other colleges. That is, IQR is low for this college. Therefore, there is a least consistence in graduation rate.

Hence, the correct answer choice is B.

d)

According to the question, the college has the highest graduation rates in one year and inconsistent graduation rates over years and has second largest IQR and range.

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Hence, the correct answer is F

e)

According to the question, the college has the lowest median and fairly consistent low graduation rates.

From the provided side by side boxplots, college E has the lowest median. Moreover, the difference between the first and third quartile is higher than college B and D. That is, IQR is higher than college B and D. The graduation rate for all the years is low as compared to other colleges. Therefore, there is a fairly consistent low graduation rate.

Hence, the correct answer choice is E

7 0
4 years ago
Help ASAP please please please
Andre45 [30]

Answer:

3 is between 1 and 2 so A. will be the correct answer

1 x 1 = 1

2 x 2 = 4

Hope this helps

Step-by-step explanation:

4 0
3 years ago
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Misha Larkins [42]
Part 1.
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B.You need substitute x by 0. x=0,
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Part 2.
A. f(x) =x², Graph is attached. 
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C. The functions will change in the point x=1
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D. Point(1,1) is closed(filled circle), point (1,3) is open(empty circle).

4 0
3 years ago
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