Find the general form of the equation for the quadratic that passes through the points (2,5) and (4,10)

Mathematics

1 answer:

astraxan [27]3 years ago

4 0

Answer:

The answer to your question is 5x - 2y = 0

Step-by-step explanation:

Data

A (2, 5)

B (4, 10)

Process

1.- Determina the slope of the line

slope = m = (y2 - y1) / (x2 - x1)

x1 = 2 y1 = 5 x2 = 4 y2 = 10

-Substitution

m = (10 - 5) / (4 - 2)

-Simplification

m = 5/2

2.- Find the equation of the line in the general form

y - y1 = m(x - x1)

-Substitution

y - 5 = 5/2(x - 2)

-Simplification

2(y - 5) = 5(x - 2)

2y - 10 = 5x - 10

5x - 2y - 10 + 10 = 0

-Result

5x - 2y = 0

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$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$9000\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\

t=years\to &9
\end{cases}
\\\\\\
A=9000\left(1+\frac{0.06}{2}\right)^{2\cdot 9}$