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3 years ago

Need help pleaseeeee!!!!!!!!!

Mathematics

1 answer:

kenny6666 [7]3 years ago

8 0

Answer:

y = 3^x is the answer as the others are quadratic or cubic functions.

Quadratic graphs are always pointing upwards or downwards, while cubic graphs have 1 end up and 1 end down.

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Just want to make sure that I did my maths right. anyone helps. thanks

ahrayia [7]

Yes you got them all correct at least I think.

5 0

3 years ago

Read 2 more answers

A collection of coins consists of nickels, dimes, and quarters. There are three fewer quarters than nickels and six more dimes t

weeeeeb [17]

Answer:

You have 15 dimes. You have 9 quarters. You have 12 nickels

Step-by-step explanation:

lets set some variables:

let "n" = the number of nickels

let "d" = the number of dimes

let "q" = the number of quarters

So, the total amount of money you have should be: $4.35 = 0.25q + 0.10d + 0.05n

Now let's look at the relationships between the coins:

"There are three fewer quarters than nickels": n - 3 = q

"six more dimes than quarters": q + 6 = d

So now you have three equations with three variables, all you need to do is solve.

$\left \{ {{4.35 = 0.25q + 0.10d + 0.05n} \atop {n - 3 = q}} \atop {q + 6 = d}}\right.$

first, you can substitute "n-3" for "q" (according to the 2nd equation) in the 1st and 3rd equation, you get:

$\left \{ {{4.35=0.25(n-3)+0.10d+0.05n} \atop {(n-3)+6=d}} \right.$

You now only have two equations and two variables.

Simplify:

$\left \{ {{4.35=0.25n-0.75+0.10d+0.05n} \atop {n+3=d}} \right.$

$\left \{ {{4.35=0.30n-0.75+0.10d} \atop {n+3=d}} \right.$

Now substitute "n+3" for "d" (according to the 2nd equation) in the 1st equation:

4.35=0.30n-0.75+0.10(n+3)

simplify:

4.35=0.30n-0.75+0.10n+0.30

4.35=0.40n-0.45

4.35+0.45=0.40n

4.80=0.40n

n=12

You have 12 nickels. Now sub "n" back into your equations to find the number of dimes and quarters:

n - 3 = q

12 - 3 = q

q = 9

You have 9 quarters.

q + 6 = d

9 + 6 = d

d = 15

You have 15 dimes.

3 0

3 years ago

A cylinder with radius 3 feet and height 5 feet is shown.

Leviafan [203]

Answer:

The volume of the cylinder is <u>141.23 cubic feet </u>

Step by step explanation :

<u>Given</u>-

Radius of cylinder = 3 feet
Height of cylinder = 5 feet

Now, we know that

<h3> $\boxed {\mathfrak \red{ volume \: of \: cylinder = \pi {r}^{2} h}}$ </h3>

where, r is the radius of the cylinder & h is the height of the cylinder.

Now,

Volume of the cylinder = $\frac{22}{7} \times {3}^{2} \times 5$

$= \frac{22}{7} \times 3 \times 3 \times 5$

$= 141.428571$ ( approximately )

$= \boxed{ 141.43 \: \mathfrak { {ft}^{3}} }$

6 0

2 years ago

Please help me ASAP!

FinnZ [79.3K]

A. d=50t B. 50,100,150,200,250 C. 50 days

5 0

3 years ago

Giá trị x thoả mãn x(x − 3) + x − 3 =0 là

svet-max [94.6K]

Here we will use the trial and error method.

We will try putting different values of x.

$\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}$

<h2>Again,</h2><h3>x=3</h3>

$\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}$

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>

5 0

3 years ago