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3 years ago

Which set of numbers is in order from least to greatest?

Mathematics

2 answers:

kherson [118]3 years ago

7 0

Hello.

The answer is: B: 364,798 < 367,259 < 367,313

A is not right because it 367 to 364 when 364 comes before 367

Its not C because of 367,313 to 367, 259 whats wrong is the last 3 numbers 259 comes before 313

Have a nice day

ozzi3 years ago

5 0

Eliminate A immediately, because "367,259 < 364,798" is false.

Elim. C because "367,313 < 367,259" is false.

Thus, B is the correct answer.

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In which quadrant will the following points be plotted (-4;-4) (5;2) (-6;11)

AVprozaik [17]

(-4,-4) is quadrant 3
(5,2) is quadrant 1
(-6,11) is quadrant 2

3 0

3 years ago

Given points A(-1, -2) and B(2, 4) where AP: BP=1:2, find the locus of point P.

koban [17]

Answer:

$x^2 + 4x + y^2 +8y = 0$

Step-by-step explanation:

Given

$A = (-1,-2)$

$B = (2,4)$

$AP:BP = 1 : 2$

Required

The locus of P

$AP:BP = 1 : 2$

Express as fraction

$\frac{AP}{BP} = \frac{1}{2}$

Cross multiply

$2AP = BP$

Calculate AP and BP using the following distance formula:

$d = \sqrt{(x - x_1)^2 + (y - y_1)^2}$

So, we have:

$2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

$2 * \sqrt{(x +1)^2 + (y +2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

Take square of both sides

$4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2$

Evaluate all squares

$4 * [x^2 + 2x + 1 + y^2 +4y + 4] = x^2 - 4x + 4 + y^2 - 8y + 16$

Collect and evaluate like terms

$4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20$

Open brackets

$4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20$

Collect like terms

$4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y + 20 - 20 = 0$

$3x^2 + 12x + 3y^2 +24y = 0$

Divide through by 3

$x^2 + 4x + y^2 +8y = 0$

3 0

3 years ago

The area of a rectangle is 48 cm² and the length of the rectangle is 8 cm longer than the width. What is the equation you would

ehidna [41]

48= l*w
l= 8+w

To solve for width, substitute the value of l in the first equation so that everything is in terms of w.

Final answer: 48= (8+w)*w

5 0

3 years ago

The vertex of the parabola below is at the point (2,4), and the point (3,6) is

lukranit [14]

Answer:

A. y= 2(x - 2)2 + 4

Step-by-step explanation:

vertex having an x value of 2 means the phrase in paren must be x - 2.

This eliminates B and D

vertex having a y value of 4 is of no help as the remaining two equations will result in 4 if the x term is 2

plugging in x = 3 makes y = 6 in equation A, but not in equation C where y = 10

3 0

3 years ago

Find the length of the line joining the points A(-2,10) and B(-8,2)

Vesnalui [34]

Length of the line

= $\sqrt{((-2)-(-8))^{2}+(10-2)^{2} }$

= $\sqrt{36+64}$

= $\sqrt{100}$

= 10

6 0

1 year ago