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GREYUIT [131]
3 years ago
12

Order these from least to greatest: 38%, 8/25, 0.41

Mathematics
1 answer:
Anna35 [415]3 years ago
5 0

Answer:

8/25 , 38%, 0.41

Step-by-step explanation:

This should be the correct answer. Hope this helps!

You might be interested in
8−i
GalinKa [24]

Hi Veracity,

Answer:

(2 + i) = 2

Step-by-step explanation:

Multiply the denominator and numerator by the conjugate,

= \frac{(8 - i)(3 + 2i)}{13}

Combine Like Terms,

= \frac{26 + 13i}{13}

Simplify,

= 2 + i

Hope This Helps :)

3 0
2 years ago
Sally lives in City A and works for the department of transportation. She needs to inspect the weigh stations in each of four di
galben [10]

Answer:

She can visit the cities in 192 ways

Step-by-step explanation:

If Sally starts from city A and after going to 4 cities she returns to home,

then that can be in 4! = 24 ways. (permutation of 4 distinct objects)

If between the time she visits cities, she comes home once,

then cities can be visited in,

4! \times 3_{C_{1}} = 72 ways.  (permutation of 4      distinct objects  and choosing 1 gap among the 3 )

If between the time she visits cities, she comes home twice,

then cities can be visited in,

4! \times 3_{C_{2}} =72 ways. (permutation of 4 distinct objects and finding 2 gaps among the 3)

If between the time she visits cities, she comes home thrice,

then cities can be visited in,

4! \times 3_{C_{3}} = 24 ways. (permutation of 4 distinct objects and choosing 3 gaps among the 3)

Now, she can't come home more than thrice in between the time she visits cities (since there are 4 cities to visit only)

So, the number of ways she can visit cities = (24+ 72 + 72 + 24)

                                                                       = 192

6 0
3 years ago
Cupro-nickel coins are minted by mixing copper and nichel in the ratio 4:1
Softa [21]
Copper:   Nickel =  4:1

a) How much copper needed for 20 kg nickel
                 C:N = 4: 1 
                 C:20 = 4:1

C/20 = 4/1       Cross Multiply
C*1 = 4*20
C = 80     

80kg Copper would be needed.

b) How much Nickel would be needed for 20 kg of Copper
                 C:N = 4: 1 
                 20:N = 4:1

20/N = 4/1       Cross Multiply
4*N = 1*20
4N = 20   Divide both sides by N.  

N = 20/4 = 5

5kg Nickel would be needed.
8 0
3 years ago
6(t-2)-76=-142 solve for t
Bad White [126]

Answer:

t= -9

Step-by-step explanation:

Add 76 to both sides

6(t-2)= -142+76

Simplify -142+76 to -66

6(t-2)=-66

Divide both sides by 6

t-2= -66/6

Simplify 66/6 to 11

t-2= -11

Add 2 to both sides

t= -11+2

Simplify -11+2 to -9

t= -9

I hope this helps you

5 0
3 years ago
Read 2 more answers
What would x be in this problem?
luda_lava [24]

Answer:

x=1

Step-by-step explanation:

6^5 = 6^x+6^4\\6^5 = 6^{x+4}\leftarrow \text {Apply product rule.}\\5=x+4 \leftarrow \text {Apply rule: If }  a^{f(x)}=a^{g(x)}\text{, then} f(x) = g(x)\\5-4=x+4-4\\\boxed {x=1}

3 0
2 years ago
Read 2 more answers
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