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Burka [1]
3 years ago
10

If f(x) = 3x - 5 and g(x) = 7x + 2, what is (f * g)(x)? NEED HELP ASAP!!!!

Mathematics
1 answer:
QveST [7]3 years ago
6 0

Answer:(f*g)(x)= 21x^2 -29x -10


Step-by-step explanation:

(3x-5)(7x+2)

21x^2-35x+6x-10

21x^2-29x-10

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Fill in the rest of the table.
Vinvika [58]

9514 1404 393

Answer:

top-down

  f(g(x)) = 1, 4, 5, 3, 2

  g(f(x)) = 5, 2, 4, 1, 3

Step-by-step explanation:

To find f(g(x)), locate g(x) in the third column (labeled g(x)). Use that value as x in the first column, then read f(x) from the second column.

Example: f(g(1)) = f(2) = 1

__

To find g(f(x)), locate f(x) in the second column (labeled f(x)). Use that value as x in the first column, and read the corresponding g(x) from the third column.

Example: g(f(1)) = g(2) = 5

6 0
3 years ago
Which of the following are square roots of —8 + 8i/3? Check all that apply.
8090 [49]

Answer:

Options (2) and (3)

Step-by-step explanation:

Let, \sqrt{-8+8i\sqrt{3}}=(a+bi)

(\sqrt{-8+8i\sqrt{3}})^2=(a+bi)^2

-8 + 8i√3 = a² + b²i² + 2abi

-8 + 8i√3 = a² - b² + 2abi

By comparing both the sides of the equation,

a² - b² = -8 -------(1)

2ab = 8√3

ab = 4√3 ----------(2)

a = \frac{4\sqrt{3}}{b}

By substituting the value of a in equation (1),

(\frac{4\sqrt{3}}{b})^2-b^2=-8

\frac{48}{b^2}-b^2=-8

48 - b⁴ = -8b²

b⁴ - 8b² - 48 = 0

b⁴ - 12b² + 4b² - 48 = 0

b²(b² - 12) + 4(b² - 12) = 0

(b² + 4)(b² - 12) = 0

b² + 4 = 0 ⇒ b = ±√-4

                     b = ± 2i

b² - 12 = 0 ⇒ b = ±2√3

Since, a = \frac{4\sqrt{3}}{b}

For b = ±2i,

a = \frac{4\sqrt{3}}{\pm2i}

  = \pm\frac{2i\sqrt{3}}{(-1)}

  = \mp 2i\sqrt{3}

But a is real therefore, a ≠ ±2i√3.

For b = ±2√3

a = \frac{4\sqrt{3}}{\pm 2\sqrt{3}}

a = ±2

Therefore, (a + bi) = (2 + 2i√3) and (-2 - 2i√3)

Options (2) and (3) are the correct options.

6 0
3 years ago
18 less than the product of 42 and x write as an algebraic expression
Afina-wow [57]
Less than = subtraction = -
Product = multiplication 

(42 + x) - 18
4 0
3 years ago
What exponential function is the best fit for the data in the table?
gogolik [260]
Answer: fourth option

\frac{1}{4} 4^{x-1}-4

Explanation:

1) the pair x = 3 f(x) = 0, leads you to probe this:

f(3) = 0 = A [4 ^ (3 - 1) ] + C = 0

=> A [4^2] = - C

A[16] = - C

if A = 1/4

16 / 4 = 4 => C = - 4

That leads you to the function f(x) = [1/4] 4 ^( x - 1) - 4

2) Now you verify the images for that function for all the x-values of the table:

x = 2 => f(2) + [1/4] 4 ^ (2 - 1) - 4 = [1/4] 4 - 4 = 4 / 4 - 4 = 1 - 4 = - 3 => check

x = 3 => f(3) = [1/4] 4^ (3 - 1) - 4 = [1/4] 4^2 - 4 = 16 / 4 - 4 = 4 - 4 = 0 => check

x = 4 -> f(4) = [1/4] 4^ (4-1) - 4 = [1/4] 4^(3) - 4 = (4^3) / 4 - 4 = 4^2 - 4 = 16 - 4 = 12 => check.

Therefore, you have proved that the answer is the fourth option.
6 0
3 years ago
Read 2 more answers
This is distance & midpoint formulas I don’t know how to solve this can anyone help?
Tasya [4]

Answer:

midpoint formula: (x₁ + x₂)/2, (y₁ + y₂)/2

distance: √[(x₂ - x₁)² + (y₂ - y₁)²]

Step-by-step explanation:

What points are you trying to calculate the distance and the midpoint for?

8 0
3 years ago
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