Answer:
Autosomal Recessive: Cystic Fibrosis, Sickle Cell Anemia, Tay-Sachs Disease. We inherit genes from our biological parents in specific ways. One of the ways is called autosomal recessive inheritance.
Explanation:
got it from google hope it help
<h2><u>Answer:</u></h2>
Sam, Tim, Bella and Joshua on the grounds that the red in Lisa is the partial blindness and they're the main individuals with the full shading red shaded.
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Explanation:</u></h3>
Red green visual impairment is a x connected characteristic, which implies that it is found on the X chromosome. X connected attributes are frequently latent, and this is the reason they for the most part appear in guys, for example, the instance of red green colorblindness.
A male has just a single duplicate of the X chromosome, so if a passive x connected characteristic is available, he doesn't have the alternative of the prevailing rendition of the quality to appear.
A latent X connected attribute can introduce itself in a female, yet since she has two X chromosomes, she would need two duplicates of the passive quality for it to introduce itself.
This is the reason visual impairment is less normal, yet at the same time conceivable in females. I trust this encourages you with your family.
It will all make more sense if you start from the beginning of the sequence with the structure of DNA. You will remember that messenger RNA contains a sequence of bases which, read three at a time, code for the amino acids used to make protein chains. Each of the sets of three bases is known as a codon.
Answer:
Zero (0)
Explanation:
According to the given information the genotype of the woman with blood type "AB" would by I^AI^B. The genotype of the man with blood type O would be "ii". Here, the alleles I^A and I^B are dominant over the allele "i".
A cross between parents with genotype I^AI^B and ii would give 50% of children with I^Ai genotype and 50% of children with I^Bi genotype. The children with "I^Ai genotype" would have blood type "A" and the children with I^Bi genotype would have blood type "B". This couple is never likely to have any child with blood type "O" since the mother does not carry allele "i".
Cross: I^AI^B x ii = 1/2 I^Ai : 1/2 I^Bi
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