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3 years ago

6

Mike 130 super bouncy balls playing basketball as schools game last night later he gave two to each of his friends this can be r

epresented by 30 minus 2F if Mike has 12 friends how many bouncy balls does Mike have left

1 answer:

Salsk061 [2.6K]3 years ago

8 0

Answer:

13469

Step-by-step explanation:

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Lucy has 4 more than 1/3 the number of pairs of socks as her sister. Lucy has at most 9 pairs of socks. How many pairs of socks

Volgvan

Answer: at most 15 pairs of socks

Step-by-step explanation:

Let the number of pair of socks of her sister be $x$ , and let the number of pairs Lucy has be $y$ .

Since , Lucy has 4 more than 1/3 the number of pairs of socks as her sister, this means that

$\frac{1}{3}x + 4 = y$ .............................. equation 1

Also , Lucy has at most 9 pairs of socks , this means that

$y\leq 9$ ....................................... equation 2

Equating the two equations , we have

$\frac{1}{3}x + 4 \leq 9$

multiply through by 3

$x + 12\leq 27$

subtract 12 from both sides

$x\leq 15$

Therefore , the sister has at most 15 pairs of socks

4 0

3 years ago

7 . Your goal is to sell at least 50 boxes of cookies for your school fundraiser.

worty [1.4K]

Answer:

a. number of boxes sold ≥ 50

b. 26 + x ≥ 50

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

5 0

3 years ago

A quadrilateral with two pairs of consecutive sides congruent and no opposite sides congruent is called a(n)

Sedbober [7]

Answer:

a kite

Step-by-step explanation:

7 0

2 years ago

Use the formula to find the length of the base next to the goal given that the height of the trapezoid is 11ft and the base fart

Liono4ka [1.6K]

Answer:

b1 = 22 ft

the length of the base next to the goal is 22 ft

Step-by-step explanation:

From the given formula;

Area A = 1/2×(b1 + b2)h ........1

Given;

Area A = 275ft^2

base b2 = 28 ft

base b1 = ?

height h = 11 ft

From equation 1;

Making b1 rhe subject of formula;

A = 1/2×(b1 + b2)h

Multiply through by 2;

2A = (b1+b2)h

b1+b2 = 2A/h

b1 = 2A/h - b2 ...... 2

Substituting the given values into equation 2;

b1 = 2(275)/11 - 28

b1 = 50 - 28

b1 = 22 ft

the length of the base next to the goal is 22 ft

5 0

2 years ago