Larger tug force = 2*cos20 forward + 2*sin20 to the right (starboard)
<span>Smaller tug force = 1*cos15 forward + 1*sin15 to the left (port) </span>
<span>Resultant force forward = 2*cos20 + 1*cos15 = 2.8453 (4dp) </span>
<span>Resultant force to right = 2*sin20 - 1*sin15 = 0.4252 (4dp) </span>
<span>Angle of resultant force = arctan(0.4252 / 2.8453) = arctan(0.1494) = 8.5 degrees</span>
I am fairly certain that the plant would lose water and that gas flow and such would occur
Answer: Time to reach max. height is the time taken by it to reach the topmost position whereas time of flight is the overall time taken by it, i.e. till it reach down back to the thrower or launcher. And also time of flight is double the time to reach maximum height.
Explanation:
Answer:
85 N
Explanation:
Given that crate mass = 20kg
Distance = 6m
Time = 3 seconds
Coefficient of kinetic friction = 0.3
We begin by calculating for acceleration
Which was gotten as 1.33 m/s sq
SEE THE ATTACHEMENT FOR DETAILS
Answer:
A. 
B. P ≈ 0
Explanation:
In order to calculate the magnetic field strength we have to use the magnetic field strength of a straight wire.
(eq. I)
B = magnetic field strength at distance d
I = current (A)
mi = represented by the greek letter μ, represents the permeability of the free space, which is: 4 × π 10^(-7) T m/A
d = distance from the wire
By replacing the values in eq I, we have the following:
(eq II)
The earth magnetic field in the surface variates from 25 to 65 microteslas. Thus:
P = Percentage from the wires/percentage of the earth
∵
∴
P ≈ 0