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Alexandra [31]
3 years ago
11

Riding in a car, you suddenly put on the brakes. As you experience it inside the car, do Newton's law apply? Do they apply as se

en by someone outside the car? Please explain reasoning, thank you!
Physics
1 answer:
alisha [4.7K]3 years ago
3 0

Answer with Explanation:

Newton's laws are applicable for inertial frames of reference which is a frame which is not accelerating when seen from the observer standing on earth.

For the person as he presses the brakes his frame is a decelerating frame of reference hence he cannot apply the newtons laws of motion as they are in their original form but if he analyses the motion he has to apply a correction known as  pseudo-force on the object he is analyzing. Pseudo Force has no basis in newton's laws but are a correction that needs to be applied if he wishes to analyse the motion from non inertial frame of reference

While as a person standing on earth outside the car since his frame is an inertial frame of reference he can apply newton's laws of motion without any correction.  

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Differences in ocean-surface height can be measured by _____.\
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<h3><u>Answer;</u></h3>

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Differences in ocean-surface height can be measured by<u> Satellite</u>

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3 years ago
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3 years ago
(b) Show that for certain incident energies there is 100 percent transmission. Suppose that we model an atom as a one-dimensiona
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Therefore using the previous result we have

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2 years ago
up off the ground a distance of 0.31 m before releasing her. Assume the partner’s velocity is zero at the beginning and the end
Anton [14]

Answer:

work done he has done is equal to 6452.712 J

Explanation:

given,                                                    

Assume the mass of the cheerleader be equal to 70.8 kg

she is lift up off to the height of 0.31 m              

acceleration due to gravity = 9.8 m/s²                        

number of time she was lift = N = 30 times

work done = N W                            

W = m g h                                          

work done = N m g h                    

work done = 30 x 70.8 x 9.8 x 0.31

                   = 6452.712 J                  

hence, work done he has done is equal to 6452.712 J

7 0
3 years ago
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