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Doss [256]
3 years ago
15

Nine more than three times x is at least 15

Mathematics
2 answers:
MariettaO [177]3 years ago
8 0

Answer:

3x+9 ≥15

Step-by-step explanation:

three times x

3x

9 more than

3x+9

is at least 15

3x+9 ≥15

AVprozaik [17]3 years ago
4 0

Answer:

Hiya there!

Step-by-step explanation:

4x + 9 = 2x - 15

Now solve for x.

                            Subtract 2x from both sides

4x-2x+9 = 2x-2x-15

2x + 9 = -15           subtract 9 from both sides

2x+9-9 = -15-9

2x = -24                  divide both sides by 2

2x/2 = -24/2

x = -12

<em><u>Hope this helped!</u></em>  ^w^

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(3z+1)(4z+2) simplify
Lorico [155]

You can FOIL (First, Outside, Inside, Last)

(3z+1)(4z+2)

First

(3z+1)(4z+2)

3z * 4z

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Outside

(3z+1)(4z+2)

3z * 2

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Inside

(3z+1)(4z+2)

4z * 1

4z

Last

(3z+1)(4z+2)

2*1

2

Combine all the products of FOIL together

12z^{2} + 6z + 4z + 2

Combine like terms

12z^{2} + 10z + 2

Hope this helped!

~Just a girl in love with Shawn Mendes

6 0
4 years ago
What is 2/3 plus 11/12 equal in a fraction
dlinn [17]

19/12

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6 0
3 years ago
Read 2 more answers
Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC . FIRST CORRECT ANSWER GETS POINTS AND BRAINLIEST!!!! T
Ad libitum [116K]

Answer:

Given : In △ABC, m∠A=60°, m∠C=45°,and AB=8 unit

Firstly, find the angles B

Sum of measures of the three angles of any triangle equal to the straight angle, and also expressed as 180 degree

∴m∠A+ m∠B+m∠C=180                      ......[1]

Substitute the values of m∠A=60° and m∠C=45° in [1]

60^{\circ}+ m\angle B+45^{\circ}=180^{\circ}

105^{\circ}+ m\angle B=180^{\circ}

Simplify:

m\angle B=75^{\circ}

Now, find the sides of BC

For this, we can use law of sines,

Law of sine rule is an equation relating the lengths of the sides of a triangle  to the sines of its angles.

\frac{\sin A}{BC} = \frac{\sin C}{AB}

Substitute the values of ∠A=60°, ∠C=45°,and AB=8 unit to find BC.

\frac{\sin 60^{\circ}}{BC} =\frac{\sin 45^{\circ}}{8}

then,

BC = 8 \cdot \frac{\sin 60^{\circ}}{\sin 45^{\circ}}

BC=8 \cdot \frac{0.866025405}{0.707106781} =9.798 unit

Similarly for  AC:

\frac{\sin B}{AC} = \frac{\sin C}{AB}

Substitute the values of ∠B=75°, ∠C=45°,and AB=8 unit to find AC.

\frac{\sin 75^{\circ}}{AC} =\frac{\sin 45^{\circ}}{8}

then,

AC = 8 \cdot \frac{\sin 75^{\circ}}{\sin 45^{\circ}}

AC=8 \cdot \frac{0.96592582628}{0.707106781} =10.9283 unit

To find the perimeter of triangle ABC;

Perimeter = Sum of the sides of a triangle

i,e

Perimeter of △ABC = AB+BC+AC = 8 +9.798+10.9283 = 28.726 unit.

To find the area(A) of triangle ABC ;

Use the formula:

A = \frac{1}{2} \times AB \times AC \times \sin A

Substitute the values in above formula to get area;

A=\frac{1}{2} \times 8 \times 10.9283 \times \sin 60^{\circ}

A = 4 \times 10.9283 \times 0.86602540378

Simplify:

Area of triangle ABC = 37.856 (approx) square unit





4 0
3 years ago
Plzzz help plzzzzzzzzzzzzzz
mezya [45]

Given:

The figure of two quadrilaterals.

In ABCD,AB=18,BC=20,CD=22,AD=24

In EFGH,EF=27,FG=30,GH=34, EH=36

To find:

Whether the figures are congruent, similar or neither.

Solution:

Ratio of corresponding sides are:

\dfrac{AB}{EF}=\dfrac{18}{27}

\dfrac{AB}{EF}=\dfrac{2}{3}

Similarly,

\dfrac{BC}{FG}=\dfrac{20}{30}

\dfrac{BC}{FG}=\dfrac{2}{3}

\dfrac{CD}{GH}=\dfrac{22}{34}

\dfrac{CD}{GH}=\dfrac{11}{17}

And,

\dfrac{AD}{EH}=\dfrac{24}{36}

\dfrac{AD}{EH}=\dfrac{2}{3}

Clearly, \dfrac{AB}{EF}=\dfrac{BC}{FG}=\dfrac{AD}{EH}\neq \dfrac{CD}{GH}.

All corresponding sides are not proportional.

Therefore, the figures are neither similar nor congruent. Hence, third option is correct.

7 0
3 years ago
What is the middle term of the product of (x - 4)(x - 3)?
irga5000 [103]
(x-4)(x-3) so what you do is
 
     x         -4
 x   x^2      -4x

-3 -3x        12

x^2-7x+12
your answer would be -7x
4 0
3 years ago
Read 2 more answers
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