Ok so the answer is D because first I solved the equation because you can’t find which answer choice it is equivalent to if you didn’t solve it ... so I solved the equation and got x=-3/2 how I solved this is
3^-x = 3^3x+6 ... since the bases are the same, set the exponents equal
-x=3x+6..... move the variable to the left-hand side and change its side
-x-3x=6 ... collect like terms
-4x = 6..... divide both sides of the equation by -4 and I got x=-3/2
I don’t want this text to be that long so they both seem calculated the same way that’s why i got -3/2 hope that helps;-;
Complete the square:
F(x) = -3x² - 6x - 5
F(x) = -3 (x² + 2x) - 5
F(x) = -3 (x² + 2x + 1 - 1) - 5
F(x) = -3 ((x + 1)² - 1) - 5
F(x) = -3 (x + 1)² + 3 - 5
F(x) = -3 (x + 1)² - 2
The y-intercept has x-coordinate equal to 0, so it corresponds to the value of F(0) :
F(0) = -3 (0 + 1)² - 2 = -3 - 2 = -5
The axis of symmetry is the vertical line running through the vertex of this parabola, so we'll come back to this.
The vertex of the parabola is (-1, -2). This represents the maximum value of F(x), which follows from
(x + 1)² ≥ 0 ⇒ -3 (x + 1)² ≤ 0 ⇒ -3 (x + 1)² - 2 ≤ -2
This is to say, every point on the parabola has a y-coordinate no greater than -2.
As mentioned earlier, the axis of symmetry is the vertical line through the vertex, and its equation is determined by the x-coordinate of the vertex. Hence the AoS is the line x = -1.
Answer:
296.89 m
Step-by-step explanation:
assuming that both the buildings are on level ground (i.e their bases are at the same elevation), see attached.
Answer:
its 3rd graph, the one with (-1,0) point
Answer:
74.36 g of aluminium acetate.
730.27g of aluminium acetate.
- to the nearest hundredth.
Step-by-step explanation:
Acetic acid is usually written as CH3COOH.
a. 6CH3COOH + Al(OH)3 ---> Al(CH3COO)3 + 9H2O
So 6 moles of acetic acid produce 1 mole of aluminium acetate.
Using the molecular masses
6*( 1.008*4 + 12.011*2 + 16 *2) g acetic acid gives (26.98+3(36.032+ 2*12.011)
348.228 g acetic acid gives 207.142 g Al acetate.
So 125 g gives (207.142 / 348.228) * 125
= 74.36 g of aluminium acetate.
b.
(26.98 + 3*16 + 3 * 1.008) g of Al(OH)3 gives 207.142 g Al acetate
78.004 g gives 207.142 g Al acetate
275 g gives (207.142 / 78.004) * 275
= 730.27g Al acetate.