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anygoal [31]
3 years ago
9

Early geneticists wondered how only four nucleotides can specify the sequence of 20 amino acids in proteins. They hypothesized t

hat there must be a code that linked the nucleotide sequence in a gene to the amino acid sequence in a protein. Each nucleotide code is called a codon. Today we know that there is a genetic code in which __________nucleotide(s) code(s) for each amino acid.
Biology
1 answer:
Ivenika [448]3 years ago
4 0

Answer:

Early geneticists wondered how only four nucleotides can specify the sequence of 20 amino acids in proteins. They hypothesized that there must be a code that linked the nucleotide sequence in a gene to the amino acid sequence in a protein. Each nucleotide code is called a codon. Today we know that there is a genetic code in which __________nucleotide(s) code(s) for each amino acid.

3

4

1

2

Explanation:

3 is the answer. 43 or 64 is the number of possible 3-letter codes that can be formed.

more than one codon can codes for the same amino acid

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Reabsorption of filtered glucose from the lumen in the pct is largely by means of:______.
Alika [10]

Reabsorption of filtered glucose from the lumen in the pct is largely by means of: secondary active cotransport.

Nephron is the functional unit of the kidney associated with removing waste products from the blood. It achieves the function by performing filtration which results in formation of urine. A nephron is divided into two parts namely renal corpuscle and renal tubule. Renal corpuscle is associated with filtration and renal tubule mainly performs reabsorption.

Renal tubules are further divided into Proximal Convoluted Tubule (PCT), loop of Henle, Distal Convoluted Tubule (DCT) and collecting duct. PCT and DCT are mainly linked with reabsorption and secretion respectively. Reabsorption in PCT occurs via cotransport. Here, glucose is reabsorbed along with sodium ions via SGLT2 cotransporter. Specifically, the reabsorption method is termed as sodium-coupled secondary active transport.

Learn more about filtration and rebasorption here -

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8 0
1 year ago
Given the fact that Amelia found this article in an on-line pop-culture science magazine, do you believe the data presented? Do
kirza4 [7]

Answer:

  • The number demonstrates that antibiotic administration can cause lengthy-term changes in the human microbiota, except for a short period of time.
  • The use of broad-spectrum antibiotics such as clindamycin poses a threat to human health. It decreases bacterial diversity while increasing and decreasing membership of certain native taxa.
  • The structure and distribution of microbials was significantly affected.
  • The use of antibiotics allows the antimicrobial resistance to be picked and enriched.
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3 0
3 years ago
How are lipids used in cellular structure
Ivanshal [37]

Answer:

hghh

Explanation:

hggh

5 0
3 years ago
Read 2 more answers
Find the unit rate with the second given unit in the denominator.
Kobotan [32]
First, the unit is words per minute, not the other way round because you're interested in how fast people can type, not how much time passes for every number of words they write or read (that would be minutes per word)

now, we know they do 4200 in 60 minutes. 

we need to divide 4200 by 60- first,\frac{4200}{60} = \frac{420}{6} = \frac{21}{3} =70

so the answer is, 70 words per minute

I think you made a typo in your answer and you meant 4600 instead of 4200 - then the answer is <span>C. 76 2/3 word/min</span>
6 0
3 years ago
Suppose the human trait for hair type is controlled by a simple dominant and recessive relationship at one locus. Curly hair, C,
myrzilka [38]

Answer:

A) The frequency of the dominant allele, C = 0.4376

B) frequency of the heterozygous genotype, Cc = 0.2461

Explanation:

Given -

Curly hair, C, is the dominant allele, and straight hair, c, is the recessive allele

Number of students with curly hair is 37

Thus frequency of genotype "CC"

= q^{2} = \frac{37}{117} \\= 0.3162

Thus, frequency of allele "q"

= \sqrt{0.3162} \\= 0.5623

As per Hardy Weinberg's first  equation-

p+q=1

Substituting the value of q, we get -

p+0.5623=1\\p= 0.4376

As per Hardy Weinberg's second equation -

p^2+q^2+2pq=1\\

Substituting the values of "p" and "q" we get -

0.4376^{2} + 0.3162+2pq = 1\\2pq = 0.2461\\

Hence,

A) The frequency of the dominant allele, C = 0.4376

B) frequency of the heterozygous genotype, Cc = 0.2461

8 0
3 years ago
Read 2 more answers
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