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3 years ago

15

Helppp...!!! please...!!!

2 answers:

vesna_86 [32]3 years ago

4 0

Answer:

middle one, it is he line of best fit

liraira [26]3 years ago

4 0

I think it is the middle one but I’m not 100% sure

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Solve for x. and please explain your answer

Natali [406]

Next to angle x is 102° and is you add 102 to angle x it has to equal 180 because that’s the value of half the circle so you do 180-102 which will give you 78

7 0

2 years ago

If a is a positive integer and b is a negative integer, which expression must be positive?

nydimaria [60]

So, let's solve all of them and see:

a - (-b) = a + b ⇒ can be either positive or negative, depending on the numbers

a + (-b) = a - b ⇒ can either be positive or negative, depending on the numbers

a * (-b) = a * (-b) ⇒ negative answer no matter what

a / (-b) = a / (-b) ⇒ negative answer no matter what

So the answer is:

<em>"None of the above"</em>.

Hope it helped,

BioTeacher101

(If you have any questions, feel free to ask them in the comments)

4 0

3 years ago

Read 2 more answers

Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)

Paladinen [302]

Answer:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

Step-by-step explanation:

Let the numbers be $x, y\ and\ z.$

Such that:

$x + y + z = 140$

Make z the subject

$z = 140 -x - y$

For their product to be maximum, we have:

$f(x,y,z) = xyz$

Substitute $z = 140 -x - y$ in $f(x,y,z) = xyz$

$f(x,y) = xy(140 - x - y)$

Open bracket

$f(x,y) = 140xy - x^2y - xy^2$

Differentiate w.r.t x and y

$f_x=140y - 2xy - y^2$

$f_y=140x - x^2 - 2xy$

Since the products are maximum, then $f_x = f_y = 0$

For $f_x=140y - 2xy - y^2$

$140y - 2xy - y^2 = 0$

Factorize:

$y(140 - 2x - y) = 0$

Split

$y = 0\ or\ 140 - 2x - y = 0$

Make y the subject

$y = 0\ or\ y = 140 - 2x$

For $f_y=140x - x^2 - 2xy$

$140x - x^2 - 2xy = 0$

---------------------------------------------------

Substitute y = 0

$140x - x^2 -2x*0 = 0$

$140x - x^2 = 0$

Factorize

$x(140 - x)= 0$

$x = 0\ or\ 140-x = 0$

$x = 0\ or\ x = 140$

---------------------------------------------------

Substitute $y = 140 - 2x$

$140x - x^2 - 2xy = 0$

$140x - x^2 - 2x(140 - 2x) = 0$

$140x - x^2 - 280x + 4x^2 = 0$

Re-arrange

$4x^2 -x^2 +140x - 280x = 0$

$3x^2 -140x = 0$

Factor x out

$x(3x - 140) = 0$

Divide through by x

$3x - 140 = 0$

$3x = 140$

$x = \frac{140}{3}$

Recall that: $y = 140 - 2x$

$y = 140 - 2 * \frac{140}{3}$

$y = 140 - \frac{280}{3}$

Take LCM

$y = \frac{140*3-280}{3}$

$y = \frac{140}{3}$

Recall that:

$z = 140 -x - y$

$z = 140 - \frac{140}{3} - \frac{140}{3}$

Take LCM

$z = \frac{3 * 140- 140 - 140}{3}$

$z = \frac{140}{3}$

Hence, the numbers are:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

8 0

3 years ago

I WILL GIVE BRAINLIEST

statuscvo [17]

4 hours = 4×60

= 240 minutes

240÷12

= 20 songs

the correct answer is 20 songs

8 0

3 years ago

Hi, i need help with these questions!

MA_775_DIABLO [31]

I hope this helps you

6 0

3 years ago