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Valentin [98]
3 years ago
8

Please help me answer this I'm having trouble

Mathematics
2 answers:
Alex777 [14]3 years ago
6 0
The first one and the last one are correct.
Allushta [10]3 years ago
4 0
1st and the last one would be correct
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REDRAGON<br>bad product lol​
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Answer:

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Step-by-step explanation:

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4 years ago
Simplify the expression. 8w + 5r – t + 9r
Wittaler [7]

Answer:

14r−t+8w

Step-by-step explanation:

Let's simplify step-by-step.

8w+5r−t+9r

=8w+5r+−t+9r

Combine Like Terms:

=8w+5r+−t+9r

=(5r+9r)+(−t)+(8w)

=14r+−t+8w

Answer:

=14r−t+8w

3 0
3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

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3 years ago
How to find the mean of percentages
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You add the two numbers and divide them by two
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