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kykrilka [37]
4 years ago
5

PLEASE HELP

Mathematics
1 answer:
Readme [11.4K]4 years ago
5 0

Answer:

x=5

Step-by-step explanation:

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PLEASE HELP ME I WILL MARK BRAINLYEST
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                               Question 9:

Given the equations

5x+2y=6;

4x-8y=0

solving the system of the equations

\begin{bmatrix}5x+2y=6\\ 4x-8y=0\end{bmatrix}

\mathrm{Multiply\:}5x+2y=6\mathrm{\:by\:}4\:\mathrm{:}\:\quad \:20x+8y=24

\mathrm{Multiply\:}4x-8y=0\mathrm{\:by\:}5\:\mathrm{:}\:\quad \:20x-40y=0

\begin{bmatrix}20x+8y=24\\ 20x-40y=0\end{bmatrix}

20x-40y=0

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\underline{20x+8y=24}

-48y=-24

\begin{bmatrix}20x+8y=24\\ -48y=-24\end{bmatrix}

-48y=-24

\frac{-48y}{-48}=\frac{-24}{-48}

y=\frac{1}{2}

y = 0.5 ( 0.5 is the result of rounding 0.5 to the nearest 0.01)

\mathrm{For\:}20x+8y=24\mathrm{\:plug\:in\:}y=\frac{1}{2}

20x+8\cdot \frac{1}{2}=24

20x+4=24

\frac{20x}{20}=\frac{20}{20}

x=1.00 ( 1.00 is the result of rounding 1 to the nearest 0.01 )

So, the solution is:

(x, y) → (1.00, 0.5)

                            Question 10)

Similarly the question 10 can be solved.

Given the equations

5x+2y=9;\:4x-3y=44

solving

\begin{bmatrix}5x+2y=9\\ 4x-3y=44\end{bmatrix}

\mathrm{Multiply\:}5x+2y=9\mathrm{\:by\:}4\:\mathrm{:}\:\quad \:20x+8y=36

\mathrm{Multiply\:}4x-3y=44\mathrm{\:by\:}5\:\mathrm{:}\:\quad \:20x-15y=220

\begin{bmatrix}20x+8y=36\\ 20x-15y=220\end{bmatrix}

20x-15y=220

-

\underline{20x+8y=36}

-23y=184

\begin{bmatrix}20x+8y=36\\ -23y=184\end{bmatrix}

-23y=184

y=-8.00   ( -8.00 Rounded to the nearest 0.01 or  the Hundredths Place )

\mathrm{For\:}20x+8y=36\mathrm{\:plug\:in\:}y=-8

20x+8\left(-8\right)=36

20x=100

x=5.00  ( 5.00 Rounded to the nearest 0.01 or  the Hundredths Place )

So, the solution is:

(x, y) → (5.00, -8.00)

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Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

To put this into slope-intercept form, you need to isolate/get the variable "y" by itself in the equation:

8x - 6y = 6     Subtract 8x on both sides

8x - 8x - 6y = 6 - 8x

-6y = -8x + 6     Divide -6 on both sides to get "y" by itself

\frac{-6y}{-6} =\frac{-8x+6}{-6}

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