Answer: cost of 1 pot of ivy = $12
Cost of 1 rose bush =$ 10
Step-by-step explanation:
Step 1
Let rose bushes be represented as r
and pot of ivy be represented as p
such that Amy who spent 82 dollars on 7 rose bushes and 1 pot of ivy can be expressed as
7 r + p = 82----- eqn 1
Rob who spent 74 on 5 rose bushes and 2 pots of ivy can be expressed as
5r +2 p = 74----- eqn 2
Step 2
Solving
7 r + p = 82----- eqn 1
5r +2 p = 74----- eqn 2
By elimination method Multiply eqn 1 by 5 and eqn 2 by 7
35r+ 5p= 410--- eqn 3
35r+ 14p =518--- eqn 4
Subtracting eqn 4 from eqn 3
9p = 108
p = 108/9
p=12
p = pot of ivy = $12
therefore rose bush wll be ( from equation 1)
7r+ p= 82
7r=82-12
7r= 70 r= 70/7
r= rose bush =$ 10
the first option is the answer
Step-by-step explanation:
4c + 6a <= 120 [building hours]
4c + 4a <= 100 [testing hours]
4 * 20 + 6 * 6 <= 120
80 + 36 <= 120
116 <= 120
true, they have enough building hours
4 * 20 + 4 * 6 <= 100
80 + 24 <= 100
104 <= 100
false, they won't have enough testing hours
the first option is the answer
Answer:
r = 10
Step-by-step explanation:
Solve for r by simplifying both sides of the equation, then isolating the variable.
X = 5.
Pythagorus Theorem:
c^2 = b^2 + a^2
(13)^2 = (12)^2 + a^2
a = sqrt((13)^2 - (12)^2))
a = 5
Answer:
30+10y < 120
Step-by-step explanation:
