Answer:
two 2
Step-by-step explanation:
First you divide the five over six into the two over three, then you add the quotient of that problem to three over four and the sum is your answer.
The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Yes! 8 - 3 is 5
so it is A.
It is not multiplied or divided by one single number so the sequence is arithmetic not geometric
hope this helps!
100-35 = 65
65% de 2300 = 1495 (mes 1)
2300-1495 = 805 (mes 2)
65% de 805 = 523,25 (mes 3)
65% de 523,25 = 340,1125 ~ 340,10 (mes 4)