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denis23 [38]
3 years ago
13

A triangle has sides that measure 4 units, 6 units, and 7.21 units. What is the area of a circle with a circumference that equal

s the perimeter of the triangle? Use 3.14 for π, and round your answer to the nearest whole number. 17 units2 24 units2 54 units2 94 units2
Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0

Step-by-step explanation:

Given that,

Sides of a triangle is  4 units, 6 units, and 7.21 units.

We need to find the area of a circle with a circumference that equals the perimeter of the triangle.

Perimeter of triangle = circumference of circle

4+6+7.21=2πr, r is the radius of circle

r = 2.73 units

Area of circle,

A=\pi r^2\\\\A=3.14\times (2.73)^2\\\\A=23.402\ \text{units}^2

or

A = 24 sq units

So, the area of the circle is 24 square units.

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3088.1931 is your answer

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5/8 -0.5 evaluate each expression. Write answer as a decimal
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The equation for picture D is 13 4/5 = w + 3 4/5. What is the solution? Write the number answer only. Please do not write the va
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2 years ago
g A population is infected with a certain infectious disease. It is known that 95% of the population has not contracted the dise
trasher [3.6K]

Answer:

There is approximately 17% chance of a person not having a disease if he or she has tested positive.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = a person has contracted the disease.

+ = a person tests positive

- = a person tests negative

The information provided is:

P(D^{c})=0.95\\P(+|D) = 0.98\\P(+|D^{c})=0.01

Compute the missing probabilities as follows:

P(D) = 1- P(D^{c})=1-0.95=0.05\\\\P(-|D)=1-P(+|D)=1-0.98=0.02\\\\P(-|D^{c})=1-P(+|D^{c})=1-0.01=0.99

The Bayes' theorem states that the conditional probability of an event, say <em>A</em> provided that another event <em>B</em> has already occurred is:

P(A|B)=\frac{P(B|A)P(A)}{P(B|A)P(A)+P(B|A^{c})P(A^{c})}

Compute the probability that a random selected person does not have the infection if he or she has tested positive as follows:

P(D^{c}|+)=\frac{P(+|D^{c})P(D^{c})}{P(+|D^{c})P(D^{c})+P(+|D)P(D)}

              =\frac{(0.01\times 0.95)}{(0.01\times 0.95)+(0.98\times 0.05)}\\\\=\frac{0.0095}{0.0095+0.0475}\\\\=0.1666667\\\\\approx 0.1667

So, there is approximately 17% chance of a person not having a disease if he or she has tested positive.

As the false negative rate of the test is 1%, this probability is not unusual considering the huge number of test done.

7 0
3 years ago
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