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denis23 [38]
3 years ago
13

A triangle has sides that measure 4 units, 6 units, and 7.21 units. What is the area of a circle with a circumference that equal

s the perimeter of the triangle? Use 3.14 for π, and round your answer to the nearest whole number. 17 units2 24 units2 54 units2 94 units2
Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0

Step-by-step explanation:

Given that,

Sides of a triangle is  4 units, 6 units, and 7.21 units.

We need to find the area of a circle with a circumference that equals the perimeter of the triangle.

Perimeter of triangle = circumference of circle

4+6+7.21=2πr, r is the radius of circle

r = 2.73 units

Area of circle,

A=\pi r^2\\\\A=3.14\times (2.73)^2\\\\A=23.402\ \text{units}^2

or

A = 24 sq units

So, the area of the circle is 24 square units.

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Anyone know how to do this? Please help
denpristay [2]

Answer:

93.6 inch^2

Step-by-step explanation:

sides=6 side-length=6 inches Apothem= 5.2 inches Area= 6*(1/2)(6)(5.2)

3 0
3 years ago
Derrick is training for a race he wants to run a total of 100 miles over 4 weeks he only runs 16 miles in the first week if he r
Gala2k [10]

Answer:

  28 miles

Step-by-step explanation:

Let w stand for the number of miles Derrick runs each week. Then after 4 weeks of training, he wants the total mileage to be 100 miles.

  16 + 3w = 100

  3w = 84 . . . . . . . subtract 16

  w = 28 . . . . . . . . divide by 3

Derrick will run 28 miles each week to achieve his training goal.

7 0
3 years ago
Calculate the volume of this prism<br> 20 cm<br> 30 cm<br> 10 cm
Ghella [55]

Answer:

6000(cm)^{3}

Step-by-step explanation:

30 \times 10 \times 20

300 \times 20

6000(cm)^{3}

<h3>Hope it is helpful...</h3>
5 0
3 years ago
Evaluate 2y when y = 6
Alina [70]

\bf \red{answer}

When,

y=6

2y=2×6=12

4 0
3 years ago
If J is the centroid of cde, de=52, fc=15, he=14, find each missing measure
const2013 [10]

Answer:

DG = 26

GE = 26

DF = 15

CH = 14

CE = 28

Step-by-step explanation:

The figure has been attached, to complement the question.

DE = 52

FC = 15

HE = 14

Given that J is the centroid, it means that J divides sides CD, DE and CE into two equal parts respectively and as such the following relationship exist:

DF = FC

CH = HE

DG = GE

Solving (a): DG

If DG = GE, then

DE = DG + GE

DE = DG + DG

DE = 2DG

Make DG the subject

DG = \frac{1}{2}DE

Substitute 52 for DE

DG = \frac{1}{2} * 52

DG = 26

Solving (b): GE

If DG = GE, then

GE = DG

GE = 26

Solving (c): DF

DF = FC

So:

DF = 15

Solving (d): CH

CH = HE

CH = 14

Solving (e): CE

If CH = HE, then

CE = CH + HE

CE = 14 + 14

CE = 28

7 0
3 years ago
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