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3 years ago

Solve for X. I really need help with problem. Please

Mathematics

2 answers:

nikdorinn [45]3 years ago

7 0

Step-by-step explanation:

I hope you can understand it

aniked [119]3 years ago

3 0

$\huge\bold{Given:}$

Angle AOB = x + 4

Angle BOC = 3x + 2

Angle AOC =90° ( ∵ it is right angle )

$\huge\bold{To\:find:}$

The value of "x".

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

$\longrightarrow{\blue{x\:=\:21°}}$

$\large\mathfrak{{\pmb{\underline{\purple{Step-by-step\:explanation}}{\purple{:}}}}}$

Since it is right-angle,

$Sum \: of \: angles \: = 90°$

$\longrightarrow{\green{}}$ x + 4 + 3x + 2 = 90°

$\longrightarrow{\green{}}$ x + 3x + 4 + 2 = 90°

$\longrightarrow{\green{}}$ 4x + 6 = 90°

$\longrightarrow{\green{}}$ 4x = 90° - 6

$\longrightarrow{\green{}}$ 4x = 84°

$\longrightarrow{\green{}}$ x = $\frac{84°}{4}$

$\longrightarrow{\green{}}$ x = 21°

$\sf\blue{Therefore,\:the\:value\:of\:x\:is\:21°.}$

Now, the two angles are

∠ AOB = x + 4 = 21° + 4 = 25°

∠ BOC = 3x + 2 = 3 x 21° + 2 = 63° + 2 = 65°

$\huge\bold{To\:verify :}$

➡ ∠ AOB + ∠ BOC = ∠ AOC

➡ 25° + 65° = 90°

➡ 90° = 90°

➡ L. H . S. = R. H. S

Hence verified. ✔

(Note:- Kindly refer to the attached file.)

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35}}}}}$

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Step-by-step explanation:

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Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2(10 \times 6)+(6 \times 10)+(10 \times 10))\\Surface \ Area \ of \ Cuboid=2(60+60+100)\\Surface \ Area \ of \ Cuboid=2(220)\\Surface \ Area \ of \ Cuboid=440\: cm^2$

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Putting values and finding surface area:

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