Answer:
The smallest possible perimeter of the triangle, rounded to the nearest tenth is 72.4 in
Step-by-step explanation:
The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side
Let
x ------> the length of the remaining side
Applying the triangle inequality theorem
1) x+x > 30
2x > 30
x > 15 in
The perimeter is equal to
P=30+2x
<em>Verify each case</em>
1) For P=41.0 in
substitute in the formula of perimeter and solve for x
41.0=30+2x
2x=41.0-30
x=5.5 in
Is not a solution because the value of x must be greater than 15 inches
2) For P=51.2 in
substitute in the formula of perimeter and solve for x
51.2=30+2x
2x=51.2-30
x=10.6 in
Is not a solution because the value of x must be greater than 15 inches
3) For P=72.4 in
substitute in the formula of perimeter and solve for x
72.4=30+2x
2x=72.4-30
x=21.2 in
Could be a solution because the value of x is greater than 15 inches
4) For P=81.2 in
substitute in the formula of perimeter and solve for x
81.2=30+2x
2x=81.2-30
x=25.6 in
Could be a solution because the value of x is greater than 15 inches
therefore
The smallest possible perimeter of the triangle, rounded to the nearest tenth is 72.4 in
Cameron has 12 fish.
The denominator in 1/3 tells you that there are THREE equal parts in the whole group. Draw 3 circles to show THREE equal parts.
Since 4 fish are 1/3 of the whole group, draw FOUR counters in the first circle.
Since there are FOUR counters in the first circle, draw FOUR counters in each of the remaining circles. Then find the total number of counters.
So Cameron has TWELVE fish in his tank
First one. PNO =22 MNO =40
