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2 years ago

Can someone please help with this question?

Mathematics

1 answer:

allsm [11]2 years ago

8 0

What’s the question lol

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Which problems can be solved by performing this multiplication?

nika2105 [10]

Answer: the fourth one

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

How do I do this please help

Umnica [9.8K]

Answer:

wrong as his calculation was incorrect at initial level itself when he found the result of the division

Step-by-step explanation:

Andre said

3 ÷ $\frac{2}{3}$

$=3 \times \frac{3}{2}$

$=\frac{3 \times 3}{2}$

$=\frac{9}{2}$

but andre calculated it as

$=4\tfrac{1}{3}$

$=\frac{4 \times 3 + 1}{3}$

$=\frac{13}{3}$

Hence his calculation was incorrect at initial level itself

4 0

3 years ago

Find the value of x and y.

Citrus2011 [14]

X would be 63, Y would be 27

A straight line is 180 degrees. 180-117=63

To find Y, since we know it is a 90 degree angle do 90-63 which is 27.

4 0

2 years ago

.Resolva as equações, sendo U = Q (separe as respostas por vírgulas). A) 3y - 2 = - y + 4 B) 5 - 4x = x + 3 + 2x C) - 12 - 9x =

Oxana [17]

Answer:

$(A) y=1.5$

$(B)x=\dfrac27$

$(C)x=2\dfrac23$

$(D)x=-5.25$

Step-by-step explanation:

(A)

$3y - 2 = - y + 4\\3y+y=4+2\\4y=6\\y=\dfrac64\\\\y=1.5$

(B)

$5 - 4x = x + 3 + 2x\\5 - 4x = 3 +3x\\5-3=3x+4x\\7x=2\\x=\dfrac27$

(C)

$-12 - 9x = - 4 - 12x\\-9x+12x=-4+12\\3x=8\\x=\dfrac83\\\\x=2\dfrac23$

(D) $- x - 6 + 3x = -2x + 8x + 15$

$2x-6 = 6x + 15\\2x-6x=15+6\\-4x=21\\x=\dfrac{21}{-4} \\\\x=-5.25$

5 0

2 years ago

Please help I will mark brainliest I'm really in need now<br> (Please explain)

Ksivusya [100]

Answer:

i think the second question (the choose the Function) means choose the function that has changed the most.

the first choose function one, i dont know but... according to wikipedia, "an initial value problem is an ordinary differential equation together with an initial condition which specifies the value of the unknown function at a given point in the domain. Modeling a system in physics or other sciences frequently amounts to solving an initial value problem." hope this helps

Step-by-step explanation:

6 0

2 years ago