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umka2103 [35]
3 years ago
14

Consider the quadratic function:

Mathematics
2 answers:
Grace [21]3 years ago
5 0

Answer:

vertex = (4, - 25 )

Step-by-step explanation:

Given a quadratic function in standard form : f(x) = ax² + bx + c : a ≠ 0

The the x- coordinate of the vertex is

x_{V} = - \frac{b}{2a}

f(x) = x² - 8x - 9 ← is in standard form

with a = 1, b = - 8, thus

x_{V} = - \frac{-8}{2} = 4

Substitute x = 4 into f(x) for corresponding value of y

f(4) = 4² - 8(4) - 9 = 16 - 32 - 9 = - 25

vertex = (4, - 25 )

Mice21 [21]3 years ago
3 0

Answer:

vertex is (4,-25)

Step-by-step explanation:

f(x) = x^2 - 8x - 9

To find out the vertex we use formula

x=\frac{-b}{2a}

From the given f(x), the value of a=1, b=-8 and c=-9

Plug in the values in the formula

x=\frac{-(-8)}{2(1)}

x=4

Now find the value of y

plug in 4 for x in f(x)

f(4) = 4^2 - 8(4)- 9=-25

The value of y is -25

The vertex is (4,-25)

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