A submarine went down 800 feet below sea level to Point A, then traveled up to Point B, which was 160 feet below sea level. Writ e the fraction that relates the distance traveled by the submarine from Point A to Point B to the depth of Point A?
1 answer:
The depth of Point A: 800 ft. The depth of the Point B : 160 ft. The distance from the point A to point B: 800 - 160 = 640 ft. The fraction is: 640 / 800 = 4/5
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