By letting

we get derivatives


a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

Examine the lowest degree term
, which gives rise to the indicial equation,

with roots at r = 0 and r = 4/5.
b) The recurrence for the coefficients
is

so that with r = 4/5, the coefficients are governed by

c) Starting with
, we find


so that the first three terms of the solution are

Answer:
Growth
Step-by-step explanation:
If the base (the number in the parentheses) is less then 1 then it is a decay, and if it's larger than 1 it is a growth.
Answer:
16m + 2n + 4
Step-by-step explanation:
( −2n −2) + (6 + 8m) + (8m + 4n)
−2n + −2 + 6 + 8m + 8m + 4n
(8m + 8m) + ( −2n + 4n) + (−2 + 6)
16m + 2n + 4