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4 years ago

Thanks guys for the help. This one and one more and I’m done!

Mathematics

2 answers:

Karolina [17]4 years ago

8 0

Answer: $60n^{3}$

Step-by-step explanation:

To find the least common multiply, you must descompose 12 and 15 into their prime factors, as you can see below:

12=2*2*3=2²*3

15=3*5

Choose the common and non common numbers with their greastest exponents:

3*5*2²=60

Now you must choose the common and non common variables with their greastest exponents:

n³

Therefore, you can conclude that the least common multiply is:

$60n^{3}$

monitta4 years ago

5 0

Answer:

60n³

Step-by-step explanation:

The least common multiple of two expressions is the value of the lowest common coefficient and variable exponent. In this case, look first at the coefficent:

12: 12, 24, 36, 48, 60

15: 15, 30, 45, 60

So, the least common coefficient is 60.

Next, look at the exponents of the variable:

n: n, n², n³

n³: n³

The combined term would be: 60n³

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You just started working for a company, where should you first look to find a confidentiality policy concerning the information

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It would be D because ur an employee and u need a handbook to see what ur handelling

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3 years ago

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

3 years ago

[Help Asap, Will Mark Brainliest] Answer is in the image,

Vera_Pavlovna [14]

Z=118 as vertically opposite angles are the same

x= (8x-50)

3 0

3 years ago

Read 2 more answers

Please solve 3(-4 + x) < -33

Dvinal [7]

Answer:

x < -7

Step-by-step explanation:

Divide both sides by 3

simplify

add 4 to both sides

6 0

3 years ago

Read 2 more answers

Create a matrix for this system of linear equations, The determinant of the coefficient matrix is

marin [14]

Answer: The determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

Step-by-step explanation: The given system of linear equations is :

$2x+y+3z=13~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\x+2y=11~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\3x+z=10~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

We are given to find the determinant of the coefficient matrix and to find the values of x, y and z.

The determinant of the co-efficient matrix is given by

$D=\begin{vmatrix}2 & 1 & 3\\ 1 & 2 & 0\\ 3 & 0 & 1\end{vmatrix}=2(2-0)+1(0-1)+3(0-6)=4-1-18=-15.$

Now, from equations (ii) and (iii), we have

$x+2y=11~~~~~\Rightarrow y=\dfrac{11-x}{2}~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)\\\\\\3x+z=10~~~~~~\Rightarrow z=10-3x~~~~~~~~~~~~~~~~~~~~~~~~~(v)$

Substituting the value of y and z from equations (iv) and (v) in equation (i), we get

$2x+y+3z=13\\\\\Rightarrow 2x+\dfrac{11-x}{2}+3(10-3x)=13\\\\\Rightarrow 4x+11-x+60-18x=26\\\\\Rightarrow -15x+71=26\\\\\Rightarrow -15x=26-71\\\\\Rightarrow -15x=-45\\\\\Rightarrow x=3.$

From equations (iv) and (v), we get

$y=\dfrac{11-3}{2}=4,\\\\z=10-3\times3=1.$

Thus, the determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

3 0

3 years ago