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aleksley [76]
3 years ago
5

What value of n makes this equation true?

Mathematics
2 answers:
anastassius [24]3 years ago
4 0

Answer:

B). n = 1.40

Step-by-step explanation:

0.7n + 0.8n = 2.1

(0.7n + 0.8n) = 2.1

1.5n = 2.1

/1.5 /1.5

n = 1.40

hope this helped!

Agata [3.3K]3 years ago
3 0

0.7n+0.8n=2.1

1.5n=2.1

n=1.4

Therefore, the answer is B.

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A triangular course for a canoe race is marked with buoys. The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg
balu736 [363]
<h2>The race is 1.2 miles long</h2>

Step-by-step explanation:

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

\texttt{Length of first leg = }\frac{3}{10}miles\\\\\texttt{Length of second leg = }\frac{1}{2}miles\\\\\texttt{Length of third leg = }\frac{2}{5}miles

Now we need to find length of race

       \texttt{Total length = }\frac{3}{10}+\frac{1}{2}+\frac{2}{5}\\\\\texttt{Total length = }\frac{3}{10}+\frac{5}{10}+\frac{4}{10}\\\\\texttt{Total length = }\frac{3+5+4}{10}\\\\\texttt{Total length = }\frac{12}{10}\\\\\texttt{Total length = }1.2miles

The race is 1.2 miles long

7 0
3 years ago
4,400 X 400 = ( blank hundreds) X ( blank hundreds) = 176 hundreds, thousands, hundrenths, tenths, tens, ones, thousands, or tho
kiruha [24]
Hello There!

(44 hundreds) x (4 hundreds) = 176 tens thousands.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
5 0
3 years ago
X4y(4) = yx2(13), calculate (x+y)2
Delicious77 [7]

Please, for clarity, use " ^ " to denote exponentiation:


Correct format: x^4*y*(4) = y*x^2*(13)

This is an educated guess regarding what you meant to share. Please err on the side of using more parentheses ( ) to show which math operations are to be done first.


Your (x+y)2, better written as (x+y)^2, equals x^2 + 2xy + y^2, when expanded.

The question here is whether you can find this x^2 + 2xy + y^2 in your

"X4y(4) = yx2(13)"


Please lend a hand here. If at all possible obtain an image of the original version of this problem and share it. That's the only way to ensure that your helpers won't have to guess what the problem actually looks like.


3 0
4 years ago
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