Answer:
b
Step-by-step explanation:
done it
Answer:
A.) gf(x) = 3x^2 + 12x + 9
B.) g'(x) = 2
Step-by-step explanation:
A.) The two given functions are:
f(x) = (x + 2)^2 and g(x) = 3(x - 1)
Open the bracket of the two functions
f(x) = (x + 2)^2
f(x) = x^2 + 2x + 2x + 4
f(x) = x^2 + 4x + 4
and
g(x) = 3(x - 1)
g(x) = 3x - 3
To find gf(x), substitute f(x) for x in g(x)
gf(x) = 3( x^2 + 4x + 4 ) - 3
gf(x) = 3x^2 + 12x + 12 - 3
gf(x) = 3x^2 + 12x + 9
Where
a = 3, b = 12, c = 9
B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)
To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula
Y = 3x + 3
X = 3y + 3
Make y the subject of formula
3y = x - 3
Y = x/3 - 3/3
Y = x/3 - 1
Therefore, g'(x) = x/3 - 1
For g'(12), substitute 12 for x in g' (x)
g'(x) = 12/4 - 1
g'(x) = 3 - 1
g'(x) = 2.
Answer:
if the village is of 120 people and 120 people are over the age of 60 then 0 people are under the age of 25.
Step-by-step explanation:
Answer:
8 , 5 , 5.785
Step-by-step explanation:
y^2 - x^3
first just plug in the numbers and you get
(4)^2 - (2)^3
Multiply
16-8 and this equals 8
x1 + x^3 - y^2
same pattern plug in the numbers
(3)^(1) + (3)^3 - (5)^2
multiply
3 + 27 - 25
P
E
M
D
Addition
Subtraction so do 3+27 first and you get
30 - 25 = 5
x^4 / x^3 plug it in
(6)^4 / (6)^3
multiply
1269 / 216
divide this and you get
5.875
Answer:
50, 40, 30, 250, 350
Step-by-step explanation:
1/2 = 0.5, 0.5 x 100 = <u>50</u> (0.5 -> 5 -> 50)
2/5 = 0.4 (10 / 5 [the denominator] = 2, 0.2 x 2 [the numerator] = 0.4), 0.4 x 100 = <u>40</u> (0.4 -> 4 -> 40)
3/10 = (10 / 10 [the denominator] = 1, 0.1 x 3 [the numerator] = 0.3), 0.3 x 100 = <u>30</u> (0.3 -> 3 -> 30)
5/2 = 2.5 (2 1/2), 2.5 x 100 = <u>250</u> (2.5 -> 25 -> 250)
7/2 = 3.5 (3 1/2), 3.5 x 100 = <u>350</u> (3.5 -> 35 -> 350)
Note: I'm not sure if I understand the question completely, but I changed the fraction into a decimal and multiplied it by 100. Not sure what it means by "<u><em>Divide</em></u><em> fraction</em>".
