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3 years ago

I will give brainliest to the correct and first answer thank you:)

Mathematics

1 answer:

insens350 [35]3 years ago

5 0

Answer:

j + 5 = 80

Step-by-step explanation:

i think thats right

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Rosa earns $12 per hour. In 7.5 hours, she will earn x dollars. Which is a valid proportion that can be used to solve the proble

Tamiku [17]

Answer:

StartFraction x over 7.5 EndFraction = StartFraction 12 over 1 EndFraction

Step-by-step explanation:

Here, in this question, given that Rosa earns $12 in an hour, she earns x dollars in 7.5 hours. So we are interested in finding the value of x.

Let’s write this in terms of proportion;

$12 = 1 hour

$x = 7.5 hours

$12 * 7.5 hours = $x * 1 hour

So this can be rewritten as;

$x/7.5 = $12/1 hour

5 0

3 years ago

Read 2 more answers

Which points lie on the graph of f(x) = logor?

Mariana [72]

Answer:

9.1

Step-by-step explanation:

cus I seen it on usatesprep

8 0

3 years ago

(x,-2) and (-9,1);slope: -3

amid [387]

Answer:

x= -10

Step-by-step explanation:

The equation is y2-y1 over x2 over x1 so

1-(-2) over -9-(x)=3

1+2=3 over -9-(x)

3/-9-x times -9-x = 3 times -9-x

3=3(-9-x)

3=-27-3x

3+27=-3x

30= -3x

-10= 3x

hope it helps man!!! :)

ps may i have brainliest so i can level up

6 0

3 years ago

A yield sign measures 30 inches on all three sides. what is the area of the sign

Nookie1986 [14]

Answer:

450

Step-by-step explanation:

To find an area of the triangle, you must first multiply the base and the height.

5 0

3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago