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laiz [17]
1 year ago
7

Help please, also provide work

Mathematics
1 answer:
Andreas93 [3]1 year ago
8 0

Answer:

9) 128
10) 78
11) 31
12) 148

Step-by-step explanation:


9) we know that the segment across from the angle 48° is double the angle.

48 · 2 = 96

The segments around the circle should all add up to 360 so we add the two segments we know to find the unknown segment.

136 + 96 = 232

360 - 232 = 128

The answer for 9 is 128.

10)

61 + 80 = 141

180 - 141 = 39

39 * 2 = 78

The answer for question 10 is 78.

11)

236 + 62 = 298

360 - 298 = 62

62 ÷ 2 = 31

The answer for question 11 is 31.

12)

50 · 2 = 100

100 + 112 = 212

360 - 212 = 148

The answer for question 12 is 148.

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Hope this is the right one.

Problem 8
p^2 - 30p + c
<em>Step One</em>
Take 1/2 of - 30
1/2 * -30 = - 15

<em>Step 2
</em>Square -15
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Problem Nine
\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a} &#10;
a = 1
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\text{x = }\dfrac{ -4 \pm \sqrt{4^{2} - 4*1*(-15) } }{2*1}
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x = [-4 +/- sqrt(76)] / 2
x = [-4 +/- 2*sqrt19]/2
x = [-4/2 +/- 2/2 sqrt[19]
x = - 2 +/- sqrt(19) 

x1 = - 2 + sqrt(19)
x2 = -2 - sqrt(19)

These two can be broken down more by finding the square root. I will leave them the way they are.  It's just a calculator question if you want it to go into decimal form.

Problem Ten

a = 1
b = 4
c = -32

The discriminate is sqrt(b^2 - 4ac)
D = sqrt(b^2 - 4ac)
D = sqrt(4^2 - 4(1)(-32)
D = sqrt(16 - - 128)
D = sqrt(16 + 128)
D = sqrt(144)
D = +/- 12

Since D can equal + or minus 12 there must be 2 possible (and different) roots. As a matter of fact, this quadratic can be factored.
(x + 8)(x - 4) = y 
But that' s not what you were asked for.
The discriminate is >  0 so the roots are going to be real.
<em>Answer; The discriminate is > 0 so there will be 2 real different roots.</em>

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