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4 years ago

How to solve algebra questions

Mathematics

1 answer:

liubo4ka [24]4 years ago

3 0

I’m not sure hope this helps you but you can go safari and it will tell you what to write

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Find the value for m<br> -10 + 59 = 5m = 7 + 3m

bearhunter [10]

-10+59=5m=7+3m

49=5m=7+3m

49-7=5m-3m

m=42/2

m=21

8 0

4 years ago

Read 2 more answers

How can knowing about an interception in football help you remember the definition of y-intercept ?

Artist 52 [7]

Answer:

Lol, no clue if this will help or not, but hopefully it does.

3 0

4 years ago

In one week, Kenny works at t hours at a cafe and earns $16 per hour. He also

Finger [1]

Answer:

t*16+b*12=how much money per week

Step-by-step explanation:

hope this helps

plz mark brainliest

6 0

3 years ago

please just give me the answer is homework please help1)vertex 2)axis of symmetry 3)x-intercepts 4)maximum or minimum 5)max/min

aniked [119]

Answer:

See explanations below

Explanation:

Vertex of a graph is the lowest point on the curve. The vertex occurs at (1.75, -2.5)

The axis of symmetry is the point on the x axis of the line that cuts through the minimum point. The axis of symmetry occurs at x = 1.75

x intercept is the point where the curve cuts the x axis. The x intercept occurs at x = 0 and x = 2.5

To get the minimum, we will use the formula;

c - b^2/4a

The equation of the curve is expressed as;

(x-0)(x-2.5)

= x (x-2.5)

= x^2 - 2.5x

a = 1, b = -2.5, c = 0

minimum = 0 - (-2.5)^2/4(1)

minimum = -6.25/4

minimum = -1.5625

Minimum value occurs at the base of the parabola. The minimum value of the function is -2.5

y intercept is the point where the curve cuts the y axis. The y-intercept occurs at y = 0.

6 0

2 years ago

Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. Here are data on the "penetr

Sonja [21]

Answer:

Step-by-step explanation:

Given that;

Compressed Soil 2.85 2.66 3 2.82 2.76 2.81 2.78 3.08 2.94 2.86 3.08 2.82 2.78 2.98 3.00 2.78 2.96 2.90 3.18 3.16

Intermediate Soil 3.17 3.37 3.1 3.40 3.38 3.14 3.18 3.26 2.96 3.02 3.54 3.36 3.18 3.12 3.86 2.92 3.46 3.44 3.62 4.26

Compressed soil intermediate soil

Mean 2.907 3.286

SD 0.1414 0.2377

Here we have,

$\bar x_1 =3.286\\ \bar x_2 =2.907\\s_1 =0.2377\\ s_2 =0.1414\\n_1=19\\n_2=20$

The pooled Standard deviation

$s_p=\sqrt{\frac{(n_1-1)s_1^2(n_2-1)s_2^2}{n_1+n_2-2} } \\\\=0.1943$

So standard error for difference in population mean is

$s_{\bar x_1 - \bar x_2} = \sqrt{\frac{s_p^2}{n_1}+\frac{s_p^2}{n_2} } \\\\=0.0623$

by inputting the values we get 0.0623

Degree of freedom for t is

df = 19 + 20 - 2 = 37,

so t-critical value is 2.715.

So required confidence interval for

$\mu_{1} - \mu_{2}$ will be

$( \bar x_1 - \bar x_2) \pm t_{critical}*s_{\bar x_1 - \bar x_2}$

$=0.3793 \pm2.715*0.063\\\\=0.3793\pm0.1690$

So required confidence interval is (0.2103 , 0.5483).

6 0

3 years ago