Please help!!! The first answerer will get brainiest! Thanks!
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The attached image shows the image of A"B"C" after the transformation
<h3>What is the transformation of the triangle about?</h3>The transformation rule states:
A"B"C" = Ro90° (T(-4,3)(ABC))
This implies that one need to rotate the triangle in a 90⁰ clockwise direction, and then one need to translate the triangle.
Using the image shown, the coordinates of ABC are;
A = (-1, 2)
B = (1, 4)
C = (3, -1)
The 90⁰ rule clockwise rotation will be:
(x,y) -- (y,-x)
So, when translated, it will be:
A' = (2, 1)
B' = (4, -1)
C' = (-1, -3)
Then the translation of the triangle using T(-4,3):
(x, y) - (x - 4, y + 3)
So, there is:
A'' = (-2, 4)
B'' = (0, 2)
C'' = (-5, 0)
Learn more about transformation from:
#SPJ1
If you mean the m^3=105, then m^6 will be ![( \sqrt[3]{105}) ^6](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B3%5D%7B105%7D%29%20%5E6)
which is 105^2 which is 11025