Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
Answer:
Size of |E n B| = 2
Size of |B| = 1
Step-by-step explanation:
<em>I'll assume both die are 6 sides</em>
Given
Blue die and Red Die
Required
Sizes of sets
- 
- 
The question stated the following;
B = Event that blue die comes up with 6
E = Event that both dice come even
So first; we'll list out the sample space of both events
Calculating the size of |E n B|
<em>The size = 3 because it contains 3 possible outcomes</em>
Calculating the size of |B|
<em>The size = 1 because it contains 1 possible outcome</em>
.01 is the answer to that or one one hundredth
Answer:
the answer is c mathematical way
3x-4y=65
3x=65+4y
x=(65+4y)/3, when y=4
x=(65+4*4)/3
x=(65+16)/3
x=81/3
x=27
