$290, 12.5%, 6 months

1 answer:

3 0

The information shown here only shows a principal sum, a rate of interest and a period or time. There is no question as to what is needed. But suppose the need is for simple interest, then we calculate using the given information and the formula: I = PRT where I is simple interest, P is the principal, R is the rate per year, and T is time P = 290, T is 6 months which is 0.5 years, R = 12.5 % which is written as 0.125 in decimal fraction. I = 290 × 0.125 x 0.5 → I = 18.125 Therefore after 6 months , the interest earned will be 18. 125 dollars

You might be interested in

Find the value of x. х 50°

xenn [34]

Answer:

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaabbbbb

Step-by-step explanation:

bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeecccccccccccccccccccccccccccccccccccaaaaaaaaaaaaaaaaaaaaaaaaaaauuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuusssssssssssssssssssssssssssssssseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

6 0

3 years ago

An old-fashioned bicycle has two differently sized wheels. The circumference of the front wheel is 9 feet larger than the circum

Lady_Fox [76]

So, the bicycle looks like the one in the picture below.

now, the circumference of the smaller wheel, will just be C = 2πr, with a radius of "r".

we also know that the large wheel has a circumference that is 9 feet larger than the small one, so, since the small one has a circumference of 2πr, then the large one will have a circumference of 2πr + 9.

after Thomas cycled for a while, the large did 500 revolutions, or times around, whilst the small one did 1400, since it's smaller. On that time, they covered however, the same amount of ground, since they're on the same bike.

The amount covered by the small one in 1400 cycles, is 1400(2πr), that's how much ground it covered.

The amount covered by the large one in 500 cycles, is 500(2πr + 9).

And we know that ground covered, is the same for both, therefore, we also know that 1400(2πr) = 500(2πr + 9).

$\bf \stackrel{small~wheel}{1400(2\pi r)}~~=~~\stackrel{large~wheel}{500(2\pi r+9)}\implies 14(2\pi r)=5(2\pi r+9)
\\\\\\
28\pi r=10\pi r+45\implies 18\pi r=45\implies r=\cfrac{45}{18\pi }
\\\\\\
\boxed{r=\cfrac{5}{2\pi }}$

so, how much ground did they cover anyway?

well, we could use either, since we know what the radius is, hmmmm let's use say the small wheel's circumference,

$\bf 1400(2\pi r)\implies 1400\left(\underline{2\pi }\cdot \cfrac{5}{\underline{2\pi }} \right)\implies 1400(5)\implies \stackrel{feet}{7000}$