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KiRa [710]
3 years ago
15

Lettuce is packaged 4 bags to a box. If there are 3.5 boxes of lettuce in the cooler how many bags of lettuce are there

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
8 0

If there are 4 bags of lettuce per whole box, 4 x 3 = 12
Then you must factor in the half of a box that can still contain lettuce, 4 ÷ 2 = 2
Which means that you would have 14 bags of lettuce total.
4 x 3 = 12
4 ÷ 2 = 2
12 + 2 = 14

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Jack wants to find out which can of pineapples is the best buy. He has a choice of four different-sized cans. Which can has the
OLga [1]

Answer:

C

Step-by-step explanation:

Here is the complete question

ack wants to fined out which can pineapples is the best buy. He has a choice of four different -sized cans. Which can has the lowest unit price per ounce?

A. 8 ounce for $ 1.44

B. 6 ounce for $ 1. 14

C. 18 ounce for $ 2.88

D. 10 ounce for $ 1.62

unit price = price / total ounces

$1.44 / 8 = $0.18

$1.14 / 6 = $0.19

$2.88 / 18 = $0.16

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5 0
3 years ago
If 2^n + 1 is an odd prime for some integer n, prove that n is a power of 2. (H
vovikov84 [41]

Step-by-step explanation:

We will prove by contradiction. Assume that 2^n + 1 is an odd prime but n is not a power of 2. Then, there exists an odd prime number p such that p\mid n. Then, for some integer k\geq 1,

n=p\times k.

Therefore

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Here we will use the formula for the sum of odd powers, which states that, for a,b\in \mathbb{R} and an odd positive number n,

a^n+b^n=(a+b)(a^{n-1}-a^{n-2}b+a^{n-3}b^2-...+b^{n-1})

Applying this formula in 1) we obtain that

2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p=(2^k+1)(2^{k(p-1)}-2^{k(p-2)}+...-2^{k}+1).

Then, as 2^k+1>1 we have that 2^n+1 is not a prime number, which is a contradiction.

In conclusion, if 2^n+1 is an odd prime, then n must be a power of 2.

4 0
3 years ago
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