-12+-12=-24
-6+-6=-12
-11+-11=-22
-10+-10=-20
-9+-9=-18
-8+-8=-16
-7+-7=-14
-5+-5=-10
-4+-4=-8
-3+-3=-6
-1+-1=-2
1+1=2
2+2=4
3+3=6
4+4=8
5+5=10
6+6=12
The value of the function 1) f -g = 2x² - 3x + 6 and 2) f(g(2)) is 3.
Here the two functions are given, f(x) and g(x).
f(x) = 2x² + 1
g(x) = 3x - 5
We have to find f-g and f(g(2)).
1) f- g
f(x) - g(x)
(2x² + 1) - ( 3x - 5)
2x² + 1 - 3x + 5
2x² - 3x + 6
2) f(g(2))
f(g(x)) = 2(3x-5)² + 1
= 2( 9x² - 30x + 25) + 1
= 18x² - 60x + 50 + 1
= 18x² - 60x + 51
f(g(2)) = 18(2)² - 60(2) + 51
=18× 4 - 120 + 51
= 72 - 120 + 51
= 123 - 120
= 3
Therefore the value of f-g is 2x²- 3x + 6 and the value of f(g(2)) is 3.
To know more about the function refer to the link given below:
brainly.com/question/11624077
#SPJ4
Answer: 90
Step-by-step explanation:
Answer:
When applicable, state the domain restriction. g(f(x)) 4 x2 + 1 16 x2 + 3 4 x2 + 7 16 x2 - 8 x + 3 Please help. I thinks that it is 16 x2 + 3. College Algebra. Consider the function f(x)=4 - x^2 for the domain [ 0,∞). Find f^−1 (x), where f^−1 is the inverse of f
Step-by-step explanation:
Answer: pay attern]dja]d
Step-by-step explanation:ad d ad ad adasd dad
