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ValentinkaMS [17]
2 years ago
7

A model length of 12cm. Represents an actual length of 102 ft. What is the scale for the model

Mathematics
1 answer:
stealth61 [152]2 years ago
8 0
102 ft = 12 cm1224 in = 12 cm1 in = 0.00980 cm
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vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
7 0
3 years ago
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larisa [96]

Answer:

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3 0
2 years ago
Read 2 more answers
Scott brought $23.25 to the art supply store. He bought a brush, a sketchbook, and a paint set. The brush was one fourth as much
fenix001 [56]

Answer:

Paint set cost = 10.5 , Sketch book cost = 7 , Brush cost = 1.75

Step-by-step explanation:

Let the cost of paint set be = p

Cost of sketchbook 's' = (2 / 3) p

Cost of brush 'b' = 1/4th of s = 1 / 4 [ (2 / 3) p ] = (1 / 6) p

Total expenditure = Money bought - Money left = 23.25 - 4 = 19.25

Total expenditure = Cost of (pen + of sketchbook + of brush) = p + s + b

= p +  (2 / 3) p + (1 / 6) p  = 19.25 → p + 2p / 3 + p / 6 = 19.25

( 6p + 4p + p ) / 6 = 19.25 → 11p / 6  = 19.25 →  p = ( 19.25  x 6 ) / 11

p = 10.5 ; s = (2 / 3) p  = 2 / 3 (10.5) = 7 ; b = (1 / 6) p  = 10.5 / 6 = 1.75

8 0
3 years ago
Write the algebraic expression to represent "Eight<br> more than a number".
fenix001 [56]

Answer:

8<x

Step-by-step explanation:

Allagater eats the bigger number

6 0
2 years ago
The velocity of a car over five hours is given by v(t)=60ln(t+1),0≤t≤5 in kilometers per hour. What is the total distance travel
algol [13]

Step-by-step explanation:

as the velocity is not constant over time, we actually have to integrate v(t) over the interval 0<=t<=5 to get the distance.

v(t) = 60×ln(t + 1)

V(t) = 60 × integral(ln(t + 1)) between 0 and 5.

integral(ln(t + 1)) = (t + 1)ln(t + 1) - t + C

V(t) = 60 × ((t + 1)ln(t + 1) - t + C)

the distance traveled between t = 0 and t = 5 is then

60 × ((5 + 1)ln(5 + 1) - 5 + C) - 60 × ((0 + 1)ln(0 + 1) - 0 + C) =

= 60×(6ln(6) - 5 + C) - 60×(1ln(1) + C) =

= 60×(5.750556815... + C) - 60×C =

= 60×5.750556815... = 345.0334089... ≈ 345 km

7 0
2 years ago
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