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gogolik [260]
3 years ago
14

Linda earns 13 dollars each hour working part-time at a bookstore. She earns one additional dollar for each book that she sells.

Let A be the amount (in dollars) that Linda earns in an hour if she sells B books. Write an equation relating A to B . Then graph your equation using the axes below. I know that is say s graph but can ya'll just give the where the points go, please and thanks.

Mathematics
1 answer:
denpristay [2]3 years ago
3 0

Answer:

A=13+B

Step-by-step explanation:

Linda earns $13  each hour working part-time at a bookstore.

Linda earns $1 for each book she sells.

Let

A be the amount (in dollars) that Linda earns in an hour;

B be the number of books Linda sells in an hour.

So,

A=13+B\cdot 1\\ \\A=13+B

The graph is shown in attached diagram

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Evaluate.
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Answer:

  -7/48

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Put the numbers in place of the corresponding variables and do the arithmetic.

  \dfrac{-\left|1\dfrac{7}{8}+(-1)\right|}{2-(-4)}=\dfrac{-\dfrac{7}{8}}{6}=-\dfrac{7}{8\cdot6}=\boxed{-\dfrac{7}{48}}

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Simplify the ratio 0.08:0.12
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4 0
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Read 2 more answers
Evaluate: <br><br>6-(2/3)^2<br><br>A. 17/3<br>B. 52/3<br>C. 49/9<br>D. 50/9​
Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

<u>....................................................................................................................................</u>

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations!  :)

\dag\textsf{Acronym \: PEMDAS}

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is \mathsf{6-(\cfrac{2}{3})^2}

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain  \mathsf{6-\cfrac{4}{9}}.

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: \mathrm{\cfrac{6}{1}-\cfrac{4}{9}}. Now let's multiply the denominator and the numerator of the first fraction times 9: \mathrm{\cfrac{54}{9}-\cfrac{4}{9}}.

See, now the fractions have the same denominator. All we should do now is subtract the numerators: \mathrm{\cfrac{50}{9}}.

∴, the answer is Option D.

Hope this helped you out, ask in comments if any queries arise.

Best Wishes!

\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach \: far. Aim \: high. Dream \: big.}}}}}\bigstar\star

\underline{\rule{300}{5}}

5 0
2 years ago
Read 2 more answers
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