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Ivanshal [37]
3 years ago
9

(- 7x + 1) - (4x - 5)​

Mathematics
2 answers:
Nutka1998 [239]3 years ago
7 0

Answer:-11x+6

Step-by-step explanation:

(-7x+1)-(4x-5)

collect the like terms and then calculate the sum

-7x+1-4x+5

-11x+1+5

-11x+6

taurus [48]3 years ago
4 0

Answer:

-11x +6​

Step-by-step explanation:

(- 7x + 1) - (4x - 5)​

Distribute the minus sign

(- 7x + 1) - 4x + 5

Combine like terms

-11x +6​

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Mrs. Reed bought 48 items for her classroom. She bought some glue bottles. She bought 5 times as many pencils as she did bottles
uysha [10]
She bought 40 pencils
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3 years ago
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Given log5 3=0.6826 and log5 8=1.2920, evaluate the expressions<br><br> Please help!?
gulaghasi [49]

Answer:

a) 1.3652

b) 1.3906

Step-by-step explanation:

a) log5 9 = log5 3² = 2log5 3 = 2(0.6826) = 1.3652

b) log5 75/8 = log5 75 - log5 8 = log5 3×25 - log5 8=

log5 3 + log5 5² - log5 8 = 0.6826 + 2 - 1.2920 = 0.6826 + 0.708 = 1.3906

3 0
2 years ago
Read 2 more answers
Can you help me find t value in this problem?
Eduardwww [97]

we have a maximum at t = 0, where the maximum is y = 30.

We have a minimum at t = -1 and t = 1, where the minimum is y = 20.

<h3>How to find the maximums and minimums?</h3>

These are given by the zeros of the first derivation.

In this case, the function is:

w(t) = 10t^4 - 20t^2 + 30.

The first derivation is:

w'(t) = 4*10t^3 - 2*20t

w'(t) = 40t^3 - 40t

The zeros are:

0 = 40t^3 - 40t

We can rewrite this as:

0 = t*(40t^2 - 40)

So one zero is at t = 0, the other two are given by:

0 = 40t^2 - 40

40/40 = t^2

±√1 = ±1 = t

So we have 3 roots:

t = -1, 0, 1

We can just evaluate the function in these 3 values to see which ones are maximums and minimums.

w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20

w(0) = 10*0^4 - 20*0^2 + 30    = 30

w(1) =  10*(1)^4 - 20*(1)^2 + 30 =  20

So we have a maximum at x = 0, where the maximum is y = 30.

We have a minimum at x = -1 and x = 1, where the minimum is y = 20.

If you want to learn more about maximization, you can read:

brainly.com/question/19819849

6 0
1 year ago
If a theater holds 1800 and sells 1/3 of its seats how many tickets does it sell
kozerog [31]

Hey!


A theater holds 1,800 seats. It sells 1/3 of it. That means you have to find 1/3 of 1,800


\frac{1800}{1} \times \frac{1}{3} = \frac{1800}{3} = 600


<em>That means the theater sells 600 seats.</em>


\framebox{Answer = 600 seats}

7 0
3 years ago
WILL MARK BRAINLIEST PLEASE HELP
Softa [21]

Answer:

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5 0
3 years ago
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