The area of a trapezium is 35 cm² and the distance between its parallel sides is 16 cm. if one of the parallel is of length 25 c
1 answer:
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Kx-3y=k
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x=
Also y=
We can not divide with zero.
k-12=0
k=12
For k= 12 equations have no solutions.
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x=
Also y=
We can not divide with zero.
k-12=0
k=12
For k= 12 equations have no solutions.
Answer:
Step-by-step explanation:
Let's see how well I can explain this. is the same as a 30 degree angle which is in quadrant 1. If you picture the unit circle, right in the center of it is the origin. If you draw a straight line from 30 degrees and through the center (the origin), you will automatically "connect" with the reference angle of 30 (this is true for ALL angles on the unit circle). This puts us in quadrant 3. In quadrant 3, x is negative and so is y. So the terminal point of the reference angle for 30 degrees has the same exact values, but both of them are negative (again, because both x and y are negative in quadrant 3). I can't see your choices but the one you want looks like this: