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NeTakaya
3 years ago
8

Phil had 93 dollars, and his sister owed 10 dollars to her friend. How much should Phil give to his sister for each of them to h

ave the same amount after she paid her debt?
Mathematics
1 answer:
slavikrds [6]3 years ago
5 0

Answer:

$51.50

Step-by-step explanation:

<em>Let the amount that Phil give to her sister be  x</em>

<em><u>After Phil's sister pays her debt of 10, Phil and her sister should have EQUAL amount. </u></em>So we can write the equation as:

93-x=x-10

Now solving this for x, we have:

93-x=x-10\\93+10=x+x\\103=2x\\x=\frac{103}{2}=51.5

Hence, Phil must give $51.50 to her sister.

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What is the domain and range of the set of ordered pairs?​
Delvig [45]

Answer:

D) would be the answer

Step-by-step explanation:

Domain is always the set of x-coordinates in the pairs and the range is always the set of y-coordinates in the pairs.

D: 7, -2, 4, -9, 0

R: 3, -2, 1, 0, 7

Put them in order from least to greatest.

D: -9, -2, 0, 4, 7

R: -2, 0, 1, 3, 7

5 0
3 years ago
Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3
Nikitich [7]

Answer:

option D

Step-by-step explanation:

f(x) = x^2 + 5x + 6

g(x)= \frac{1}{x+3}

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x  in f(x)

f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6

To simplify it we take LCD

LCD is (x+3)(x+3)

\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}

\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}

All the denominators are same so we combine the numerators

\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}

\frac{6x^2+41x+70}{x^2+6x+9}

Option D is correct

8 0
3 years ago
Read 2 more answers
A business executive bought 40 stamps for
alekssr [168]

Answer:

32 33-cent stamps, 8 23-cent stamps

Step-by-step explanation:

In order to solve this question, we need to set up a system of equations. Also known as solving for two variables (the number of each stamp).

Let's set x to be the number of 33-cent stamps. Similarly, let's set y to be the number of 23-cent stamps.

To make our first equation, let's think about the number of stamps total we have. We can say:

x + y =40

<em>(AKA - The number of 33-cent stamps, plus the number of 23-cent stamps, equals 40 stamps.)</em>

Now, let's make an equation for the cost of these stamps.

0.33x + 0.23y = 12.40

<em>(AKA - The cost of the stamps in total, should equal $12.40).</em>

So now, we have our two equations:

x + y =40\\0.33x+0.23y=12.40

If you have a TI-84 graphing calculator, you can go to apps -> polysmlt2 -> simultaneous eqn solver, and then input these equations into the menu. This will solve the problem for you.

If you need to do this manually, let's use substitution. Condense our first equation to make it more substitutable.

x+y=40\\x=40-y

Now, let's put this into our second equation.

0.33x+0.23y=12.40\\0.33(40-y)+0.23y=12.40

Distribute, and solve for y.

13.2-0.33y +0.23y =12.40\\13.2-0.1y=12.40\\-0.1y=-0.8\\y=8

Now, we plug this into one of our equations.

x+y=40\\x+8=40\\x=32

In the end, we have thirty-two 33-cent stamps, and eight 23-cent stamps.

3 0
1 year ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 436.0 gram setting. It
Vilka [71]

Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, \bar{x} = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}

We use one-tailed(left) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92

Now, z_{critical} \text{ at 0.05 level of significance } = -1.64

Since,  

z_{stat} < z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

8 0
3 years ago
Three brothers decided to share costs evenly. They bought a race track for $36.99 and a car for $18.99. How much did each brothe
lisov135 [29]
54 55.98÷3=18.66

correct answer 18.66
7 0
3 years ago
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