The permutation illustrates that if no one has been cast yet, the different ways that are there to cast Jean Valjean from the 22 men is 22.
<h3>How to compute the value?</h3>
The ways to cast Jean will be:
= 22!/(22 - 1)!
= 22!/21!
= 22
When Jean Valjean has already been cast, the different ways that are there to cast Inspector Javert from the remaining men will be:
= 21!/(21 - 1)!
= 21!/20!
= 21
When Jean Valjean and Inspector Javert have already been cast, the different ways that are there to cast Marius from the remaining men will be:
= 20!/(20 - 1)!
= 20!/19!
= 20
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Whilst it seems an unlikely scenario, unless we have reason to believe Susie is not making a random choice but is making a free selection, then the previous withdrawals make no difference as the marble is returned each time. Therefore the probability is the same as at the beginning which is 5 red / 15 total marbles, or 1 in 3.
Answer:
(- 8, 8 ) and (- 4, 1 )
Step-by-step explanation:
The solution to a system of equations given graphically is at the points of intersection of the two
They intersect at (- 8, 8 ) and (- 4, 1 ) ← solutions
We know that x = 8 and x = -5, thus
