Answer:
Step-by-step explanation:
Given is a table of x, f(x) as below
x 1 3 4 6 7 9 10
f(x) 4 8 6 10 10 12 16
Mid pt 6 7 8 10 11 14
width of
interval 2 1 2 1 2 1
dA1 12 7 16 10 22 14
area = area of all rectangles= 81 sq units.
The answer is <span>mean = 13,027; median = 12,200; no mode
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Let's rearrange values from the lowest to the highest:
11350, 12050, 12200, 13325, 16211
<span>The mean is the sum of all values divided by the number of values:
</span>(11350 + 12050 + 12200 + 13325 + 16211)/5 ≈ 13027
The median is the middle value. If there is an odd number of data, then the median is the value in the middle. In the data set 11350, 12050, 12200, 13325, 16211, the median (the middle value) is 12200
<span>The mode is the value that occurs most frequently. Since none of the number does not occur most frequently, there is no mode.
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Right side was multiplied by 6 so you multiply the left side by 6 so 72:6
To factor this fraction, you have be be aware of two special factoring formula:
a^3<span> + </span>b^3<span> = (</span>a<span> + </span>b)(a^2<span> – </span>ab<span> + </span>b^2<span>)
</span><span>(a+b)³ = a³ + 3a²b + 3ab² + b³
You can see the top part in this case is (x+y)^3, and the bottom (denominator) can be factor into (x+y)(x^2-xy+y^2)
we can cancel (x+y), so what we have left is (x+y)^2/(x^2-xy+y^2)
or (x^2+2xy+y^2)/(x^2-xy+y^2)
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