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GarryVolchara [31]
3 years ago
13

A recipe calls for 2 cups of flour to make 2 dozen cookies. use the proportion to calculate how much flour is needed to make 6 d

ozen cookies. 2 cups/2 dozen= x cups/6 dozen
a.
Mathematics
1 answer:
Fed [463]3 years ago
4 0
If 2 dozens = 2cups
   6 dozens =x
2cups/2 dozens=x cups/6 dozens
2c/2d=6d/x
multiply the first number on the left side of the equation to the last on the other side of the equation and the rest
2*x=2*6
2x=12
2x/2=12/2
x=6
Therefore  6 cups will be needed to make 6 dozens of cookies
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Answer:

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Step-by-step explanation:

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2 years ago
Which expression has a value of 22? A. 14 + 2 x 5. B. (14+2) x 5 C. 24 - 6÷ 3. D. (24 - 6) ÷ 3
zimovet [89]

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

A. 14 + 2 × 5 = 14 + 10 = 24 ≠ 22

B. (14 + 2) × 5 = 16 × 5 = 80 ≠ 22

C. 24 - 6 ÷ 3 = 24 - 2 = 22

D. (24 - 6) ÷ 3 = 18 ÷ 3 = 6 ≠ 22

<h3>Answer: C.</h3>
5 0
3 years ago
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The total number of​ restaurant-purchased meals that the average person will eat in a​ restaurant, in a​ car, or at home in a ye
zloy xaker [14]

Answer:

Number of​ restaurant-purchased meals eaten in a​ restaurant = 70

Number of​ restaurant-purchased meals eaten in a​ car = 22

Number of​ restaurant-purchased meals eaten in a​ home = 60

Step-by-step explanation:

Let the number of people that will eat in a restaurant be R.

Let the number of people that will eat in a car be C.

Let the number of people that will eat in a home be H.

From the information given in the problem we have,

R+C+H = 152 ____equation (1)

C+H-R = 12 ____equation (2)

R = H+10 ____equation (3)

1) Plugging in R=H+10 from equation 3 into the equation 2, we get

C+H-R=12

=> C+H-(H+10)=12

=> C+H-H-10=12

2) Cancelling out +H and -H, we get

C-10=12

3) Add 10 to both sides

C-10+10=12+10

4) Cancelling out -10 and +10, we get

C=22

5) Plugin C=22 in equation 1, we have

R+C+H = 152

=> R+22+H=152

Subtract 22 from both sides,

R+22+H-22=152-22

Cancelling out +22 and -22 from the left side, we get

R+H=130 ____let it be equation (4)

6) Plugin C=22 in equation 2, we have

C+H-R = 12

22+H-R = 12

Subtracting 22 from both the sides, we get

22+H-R-22 = 12-22

Cancelling out +22 and -22 from the left side,

H-R = -10 ____let it be equation (5)

7) Adding equation 4 and equation 5, we get

(R+H)+(H-R) = 130 + (-10)

=> R+H+H-R = 130-10

8) Cancelling out R and -R from the left side, we get

2H = 120

9) Dividing both sides by 2, we get

\frac{2H}{2} = \frac{120}{2}

10) Cancelling out the 2's from the left side, we have

H=60

11) Plugging in C=22 and H=60 in the equation 1, we have

R+C+H = 152

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=> R + 82 = 152

12) Subtracting 82 from both the sides, we get

R + 82 -82 = 152 -82

13) Cancelling out +82 and -82 from the left side, we get

R = 70

<em>So, C=22, H=60, R=70</em>

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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