Answer:
Option (2). 1
Step-by-step explanation:
Coordinates of point A, B, C and D are,
A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).
Quadrilateral ABCD when rotated 90° clockwise about the origin,
Rule for the rotation of the vertices,
(x, y) → (y, -x)
Following the rule of rotation coordinates of the image points,
A(-4, 4) → A'(4, 4)
B(-2, 4) → B'(4, 2)
C(-2, 1) → C'(1, 2)
D(-4, 3) → D'(3, 4)
Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.
Option (2) is the correct option.
Answer:
Step-by-step explanation:
Let the x be the number of hours after noon.
<u>We have the following equation:</u>
- 14.83 + 0.12(x + 3) = 15.33 - 0.15x
- 14.83 + 0.12x + 0.36 = 15.33 - 0.15x
- 0.12x + 0.15x = 15.33 - 15.19
- 0.27x = 0.14
- x = 0.14/0.27
- x ≈ 0.5
Answer:
Step-by-step explanation:
You can plug in the 294 for A and solve
2x²-3xy-2y²-2x-11y-12
Write -3xy as a difference
2x²+xy-4xy-2y²-2x-11y-12
write -2x as a difference
2x²+xy-4xy-2y²+4x-6x-11y-12
Write -11y as a difference
2x²+xy-4xy-2y²+4x-6x-8y-3y-12
Factor out 2x from the expression
2x×(x-2y-3)+xy-2y²+4x-8y-3y-12
Factor out y from the expression
2x×(x-2y-3)+y×(x-2y-3)+4x-8y-12
Factor out 4 from the expression
2x×(x-2y-3)+y×(x-2y-3)+4(x-2y-3)
Factor out x-2y-3 from the expression
Answer: (x-2y-3)x(2x+y+4)
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