Answer:
x<u>></u>17
Step-by-step explanation:
Answer:
slope = -1/4 intercept = 50
Step-by-step explanation:
In this problem, we can imagine that all the points
connect to form a triangle. The three point or vertices are located on the
pitcher mount, the home plate and where the outfielder catches the ball. So in
this case we are given two sides of the triangle and the angle in between the
two sides.
<span>With the following conditions, we can use the cosine law
to solve for the unknown 3rd side. The formula is:</span>
c^2 = a^2 + b^2 – 2 a b cos θ
Where,
a = 60.5 ft
b = 195 ft
θ = 32°
Substituting the given values:
c^2 = (60.5)^2 + (195)^2 – 2 (60.5) (195) cos 32
c^2 = 3660.25 + 38025 – 20009.7
c^2 = 21,675.56
c = 147.23 ft
<span>Therefore the outfielder throws the ball at a distance of
147.23 ft towards the home plate.</span>
Answer:
26
Step-by-step explanation:
18 - 2^4 * (-0.5)
Calculate 2 to the power of 4 and get 16.
18−16(−0.5)
Multiply 16 and −0.5 to get −8.
18−(−8)
The opposite of −8 is 8.
18+8
Add 18 and 8 to get 26.
26
The given quadrilateral ABCD is a parallelogram since the opposite sides are of same length AB and DC is 4 and AD and BC is 2.
<u>Step-by-step explanation</u>:
ABCD is a quadrilateral with their opposite sides are congruent (equal).
The both pairs of opposite sides are given as AB = 3 + x
, DC = 4x
, AD = y + 1
, BC = 2y.
- AB and DC are opposite sides and have same measure of length.
- AD and BC are opposite sides and have same measure of length.
<u>To find the length of AB and DC :</u>
AB = DC
3 + x = 4x
Keep x terms on one side and constant on other side.
3 = 4x - x
3 = 3x
x = 1
Substiute x=1 in AB and DC,
AB = 3+1 = 4
DC = 4(1) = 4
<u>To find the length of AD and BC :</u>
AD = BC
y + 1 = 2y
Keep y terms on one side and constant on other side.
2y-y = 1
y = 1
Substiute y=1 in AD and BC,
AD = 1+1 = 2
BC = 2(1) = 2
Therefore, the opposite sides are of same length AB and DC is 4 and AD and BC is 2. The given quadrilateral ABCD is a parallelogram.
