Find the soultion(s) to the system of equations. Select all that apply

Mathematics

1 answer:

neonofarm [45]3 years ago

3 0

Answer:

(0,-3)

(3,0)

Step-by-step explanation:

The solutions to the system of equations are where the two graphs cross

The first is at x=0 and y=-3

The second is at x=3 and y=0

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The price of gasoline has increased from $2.00 per gallon to $3.00 per gallon. how would this price change be represented on the

vladimir2022 [97]

If the price of gasoline has increased from $2.00 per gallon to $3.00 per gallon. how would this price change be represented on the demand curve is: a movement from one point on the line to a higher point on the line.

<h3>What is demand curve?</h3>

Demand curve can be defined as the curve that show price of goods and services produced as well as the quantity demanded for the goods produce at a particular period of time.

The price change can be represented on the demand curve when price increase and this happen when the price of goods move from one point on a line to a higher point on the line

Therefore how would this price change be represented on the demand curve is: a movement from one point on the line to a higher point on the line.

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5 0

1 year ago

Unit 3, Lesson 7

aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

Given:

A car travels 55 miles per hour for 2 hours.

So the speed of the car 55 miles per hour is constant for 2 hours.

Using speed formula.

$Speed=\frac{distance}{time}$

Second row.

From the second row of the table $time = \frac{1}{2}=0.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{0.5}$

$distance = 55\times 0.5$

$distance = 27.5\ mi$

Third row.

From the third row of the table $time =1\frac{1}{2}=\frac{3}{2} = 1.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.