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Romashka-Z-Leto [24]
3 years ago
11

What is the value of the 1 in 9.154

Mathematics
1 answer:
Andrej [43]3 years ago
5 0
What is the value of 1 in 9.54, The value of the one is 1 tenth its in the tenths spot

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397 students went on a field trip. Eight
lbvjy [14]

Answer:48

Step-by-step explanation:

Total number of students=397

Students that travelled in a car=29

Let the students that travelled in a bus be represented by y.

Since 8 buses were filled, it will be 8y for total students

8y + 29= 397

8y= 397-29

8y= 368

Divide both side by 8

8y/8=368/8

y = 46

Number of students in each bus is 46

8 0
3 years ago
2 4/5 divided by 2/15
REY [17]

Answer:

21

Step-by-step explanation:

3 0
3 years ago
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In a given year, the average annual salary of a NFL football player was $189,000 with a standard deviation of $20,500. If a samp
nika2105 [10]

Answer:

15.15% probability that the sample mean will be $192,000 or more.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 189000, \sigma = 20500, n = 50, s = \frac{20500}{\sqrt{50}} = 2899.14

The probability that the sample mean will be $192,000 or more is

This is 1 subtracted by the pvalue of z when X = 192000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{192000 - 189000}{2899.14}

Z = 1.03

Z = 1.03 has a pvalue of 0.8485.

1-0.8485 = 0.1515

15.15% probability that the sample mean will be $192,000 or more.

7 0
3 years ago
Need help 2x = 2(x-3)
GenaCL600 [577]

Answer:

0=-6 There can't be an answer for x

Step-by-step explanation:

1: distribute: 2x=2x-6

2: isolate x by subtracting 2x from both sides: 0=-6

3 0
3 years ago
Read 2 more answers
Help lol! the explanation is on the bottom!!
Slav-nsk [51]

Answer:

1 =80

2 =100

3 =80

4 =100

6 = 100

7 =80

8 =100

Step-by-step explanation: since 5 and 7 are the same, if u slide the bottom up to the top, 1 and 3 would be the same as 5 and 7

2,4,6,and 8 are 180-80 which equals 100

3 0
3 years ago
Read 2 more answers
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