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3 years ago

(5y 3 + 20y 2 – 12)(2y3 - 15y2 + 4y + 16)

Mathematics

1 answer:

Alex3 years ago

8 0

Answer:

225y5-192

Step-by-step explanation:

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Simplify (4ab^2)^3<br><br> Any help is appreciated

Pie

Answer:

$64a^{3} b^{6}$

Step-by-step explanation:

1) Distribute the exponent outside of the parentheses to the terms inside the parentheses. In this case, multiply the 3 outside the parentheses with the exponent of each of the terms inside:

$(4ab^{2} )^3$

$4^{3}$ · $a^{3}$ · $b^{6}$

2) The variables are fine - you can't simplify them further. All you need to do now is multiply the $4^{3}$ out. Remember that it's kind of like asking, "what is 4 × 4 ×4?"

$4$ · $4$ · $4$ · $a^{3}$ · $b^{6}$

$16$ · $4$ · $a^{3}$ · $b^{6}$

$64a^{3} b^{6}$

Therefore, $64a^{3} b^{6}$ is the answer.

3 0

3 years ago

I WILLL GIVEE BRAINLIESTTTT

BARSIC [14]

Answer: A

Step-by-step explanation:

3 0

2 years ago

a ribbion is 3 2/3 yards long. Mae needs to cut the ribbion into pieces that are 2/3 yard long.how much ribbion will be left aft

Lemur [1.5K]

To answer this question you need to divide to get the number of pieces and then multiply whats leff by 3 2/3.

Divide 3 2/3 by 2/3. There are a few ways to do this but I am going to turn 3 2/3 into an improper fraction and then divide.

So $3\frac{2}{3} = \frac{11}{3}$
Now divide
$\frac{\frac{11}{3}}{\frac{2}{3}}$
$\frac{11}{3} \times \frac{3}{2} = \frac{11}{2} = 5\frac{1}{2} = 5.5$

We can see she can get 5.5 pieces at 2/3. So .5 is going to be left over so we ask our self, what is .5 of 3 2/3? We times .5 by 3 2/3 = 1.83 yards left. If you want it into a fraction, it would be $1\frac{83}{100}$ yards left

7 0

3 years ago

There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student

Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

$\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57$

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0

3 years ago

If 15% of an item is $18.00 what was the original price?

larisa [96]

<span>from the whole price,
15% of this price is equal to $18.00.
therefore if 15 % equals $18.00

then 100% is the original price therefore 100 % = 18.00 / 15 % x 100% = $120 therefore original price = $120</span>

5 0

3 years ago

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